If the above link expires, https://gist.github.com/x0r19x91/86cc229c48daccaa4b568b11bdcbbaf1 |
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If my analysis is correct, the crackme source is https://dpaste.org/j0Jz |
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If i am not wrong, the answer is ed55d0092b90e824c9c1df7db6816ce5 right? |
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Great Challenge! |
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Nice Challenge!
sha512(flag) = ea378c8d8c0dc905eef43b9f0d67113f7b1d851ce55845273a6727dc016b89f0eb54e17de05fa8bea77907301f30a75939f8c468d7a24c9f15e1799740dc9df2 |
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guess == millis % (sumOfDigits(micros)*micros) |
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This is a level1 crackme. I don't understand why it's mislabeled as level4.
Password: godpowisacraftyfellow
AES.Key: pjqFVqerYiTPHmP6Lno7ARDjrRv0IIM3
AES.IV: N5GQ5lzVbkKiXuGo |
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Awesome! Gratz! |
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https://paste.ubuntu.com/p/nNm3p2qYMQ/ |
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If the flag says you're lost, then its the wrong flag :)
The real flag won't say that you're lost |
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Sorry @Gautam, it's not the flag :) |
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Please provide a plaintext code, instead of pdf! |
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It's unsolvable. Its just comparing a heap address with a data section address. |
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Unpacked EXE
https://mega.nz/#!lVZTlQpK!2twSIZjjmdwPEXDh0P1dM_cyLr4RYJ_94z37Mupp1EY |
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Unpacked!!!! |
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2sl0--424 |
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I don't understand why it's rated 3. It's rating should be 2.
Don't get misled by the rating.
- fucking_m0rfing |
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Solved It! |
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@jeffli6789 nice solution! The validation algorithm is actually a deterministic finite automaton and buf2 is the transition function |
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Did anyone solve it btw ? |
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I guess the difficulty might be 3 |
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I can |
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lol I wrote it myself... This is no virus |
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Solved It!
Sha256 - aeb74bc6ce8947b0929cde995eae923234002d10a1d63f59ab893fe4687687d7 |
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Please add an MIPS/ARM/x86/AMD64 arch binary |
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Excellent Solution @4aca7f6c :-) |
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The sha512 of the solution is b9d9c8b32a89a7152562b586654663459865784d7a75302b695cb2aabd9eb4b7bfcad9452e611e24748d4c3ba5f1306ef4f456a0d6f3d97a159dc6cfe7ce748e |
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Highly obfuscated.Got to analyze closely |
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The SHA256 of the solution is 21f2049d5b7a94430621acbc5f6c467c134d368a2c69a8283cc08b1f6183962c |
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Nice ROP ! |
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It's not a hard challenge I guess |
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That's the intended password ! Well done @4aca7f6c |
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That bug causes it to have multiple solutions. But it won't be hard if you can guess the charset :-) |
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There is a bug. I'll patch and upload it soon.
Sorry for the inconvenience |
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Solved It ! It was a nice crackme :-) Thanks |
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It would have been better if there was a discord channel |
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But ArithMetic Exception |
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I got EAX = 0 |
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Easy. Chaining characters |
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Nice ! The activation code is constant |
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Nice Challenge @P45H3 ! The SHA256 of the password is 6f388c2957a905adf7d81de681761700fceb10f2c835df5b78902de73d781116 |
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This was an easy challenge I guess. |
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Very easy crackme, using a FSM. Here are some keys
aaVf!zh9i2
aaVf!zh9j2
aaVf!zh9k2
aaVf!zh9l2
aaVf!zh9m2
aaVf!zh9o2
aaVf!zh9p2
aaVf!zh9q2
aaVf!zh9r2
aaVf!zh9s2
aaVf!zh9t2
aaVf!zh9u2
aaVf!zh9v2
aaVf!zh9w2
aaVf!zh9x2
aaVf!zh9y2
aaVf!zh9z2
aaVf!zh9!2
aaVf!zh9@2
aaVf!zh9#2
aaVf!zh9$2
aaVf!zh9%2
aaVf!zh9^2
aaVf!zh9&2
aaVf!zh9*2
aaVf!zh9(2
aaVf!zh9)2 |
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Great Challenge ! |
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