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Crackme Author Summary Date Action
BabyRev Slavetomints 2025-02-26 19:04 View
mihawkre Vanzen Pretty simple, "find the key in the code and plug it in" kind of problem. 2025-02-17 00:18 View
BabyRev Aotrix 2025-02-16 00:50 View
Password-cmd Vanzen Not a super clear success state, fairly certain I did this right though. Write-up attached. 2025-02-15 23:14 View
Switching crackme Snxhit Detailed overview, with keygen and decompiled source inside :) 2025-02-15 18:47 View
.net_crackme_no.1 by subminking Vanzen Nice easy one, text writeup including a small program attached. 2025-02-14 22:42 View
Beginner slither (Recommended for beginners and their first crack with DNSpy)check solution.txt 2025-02-14 00:35 View
Sexy 1337 SaHHiiLL includes a keygen.c 2025-02-13 13:20 View
easy keyg3nme Snxhit This crackme is fairly simple, it just checks for to see if the entered key is divisible by 1223. I also made a three line python script to output a random key which will work, since I didn't know how exactly this was to be keygen'd. It is a good crackme for beginners to the world of reverse engineering such as myself. Had fun, thanks Ezman! 2025-02-12 19:03 View
easy_reverse fieldhamster 2025-02-11 23:42 View
BabyRev Sanca tehee 2025-02-05 19:00 View
easy_reverse Sanca my first crackmes problem 2025-02-05 18:34 View
VeryEasyCrackme ver02 I opened the executable in IDA Free and inspected the main function, where I found that the password was in plaintext and was hardcoded as "YourPass". The program performs two anti-debugging checks: CheckDebug() uses IsDebuggerPresent() to detect a debugger, and CheckDebug2() checks for a debugger via an IAT function. To bypass these checks, I modified the RIP value to skip over both functions and prevent the program from calling ExitProcess(). 2025-02-04 07:19 View
first crakme xor Koalko The password length in the program is constant and equals 8. After entering the password, the program goes through the password 3 times, using XOR encryption (xorEncryptDecrypt) with the values ​​75, 76 and 77. It is easy to calculate that 75^76^77 = 74. The calculateChecksum function returns the sum of the ASCII values ​​of the characters in the string. Therefore, to build the password, we need to find values ​​such that when XORed with 74 and subtracted from 300, they will be multiples of 7 (since the original password length is 8, and now we are calculating the index of the first value). Once we find the first value of the password, we can calculate the next character and repeat it 7 times. To calculate the next character, we keep temporary variables for convenience. Let A be the missing sum for the checksum, then A = 300 - (index ^ 74). Let B be the XOR value of the required character. Since we need to fill 7 characters and A is a multiple of 7, then B = A / 7. So the required character index is B^74. The general formula is: (300 - (i^74)) / 7) ^ 74 2025-01-31 00:04 View
Insanely Simple CrackMe CreHx I used Hex Editor and simply looked into the exe I selected the text I thought was the correct password, I was right 2025-01-26 09:21 View
EZ crackme zaer777 simple challenge to warm up 2025-01-20 23:17 View
crack me funny lvl 2 Benbaby Explaination. It's really good for starting static analysis. 2025-01-18 16:34 View
crypted string crackme Pau1CTFer Dynamic analysis techniques 2025-01-18 07:00 View
Rose.exe CZ-DannyK Monster solution for this amazing crackme. 2025-01-17 21:18 View
Winforms License key Validation crackme framekop Goal, How IT work, Solution. Everthing in the PDF file. 2025-01-12 15:55 View
Easy Crackme Benbaby It's OK. Explaination is attached. 2025-01-11 15:15 View
Baby Keygen 2 jhosuakz Thanks 2025-01-10 15:21 View
CrazyCrackMe jmpeax Explanation and keygen 2025-01-07 19:20 View
Simple Keygen carougeno Solution in a .txt (Cutter) 2025-01-06 15:11 View
CrackMe OS | Part 1 Benbaby Thanks Lxwxrs. It's good. Including explaination and source code. 2025-01-05 15:51 View
CrYP70NYM'S CRACKME FIXED Benbaby I hate random. Explaination & source code. 2025-01-05 04:37 View
LoginCrackme Benbaby It's OK. Explaination and code. Thanks Bros. 2025-01-03 17:31 View
pAsSwoRD_GO Andrysqui A solution to this CrackMe by decompiling/disassembling the code and inspecting it to crack the password as it's only encoded, plus explanations to everything. 2025-01-01 18:45 View
Hard work bro Tut Download the solution 2025-01-01 12:43 View
zun1 crackme bernas198YT I hope you understand my explanation 2024-12-31 19:14 View
mihawkre wepinek Simple dnSpy knowledge 2024-12-31 10:06 View
StillAching's CrackMe Adb2 2024-12-29 09:38 View
nasm crack Shun 2024-12-27 16:24 View
guess_the_password Shun 2024-12-27 15:28 View
zuha crackme Benbaby Explain how to do. Thanks ChatGPT told me such ideal. 2024-12-25 16:16 View
SecretKeyCrackme Benbaby Explaination and script. 2024-12-25 14:52 View
Fatmike's Crackme #2 Benbaby LSD crackme. But absolutelly good. Including explain and source code of keygen. 2024-12-22 18:22 View
my first crackme Benbaby Explain & source code of keygen. Thanks 2024-12-22 04:38 View
Sexy 1337 vsalce01 2024-12-16 05:55 View
Plain sight fuzzybear 2024-12-14 21:46 View
Find password ax4w very nice, explanation, solution and c code in the file. 2024-12-13 20:04 View
TryCrackMe ax4w 2024-12-13 18:52 View
TryCrackMe (v1) Benbaby Note and source code of keygen. It’s OK. Clear encrypt function and easy to follow. 2024-12-13 17:06 View
Fatmike's Crackme #6 CZ-DannyK Solution for this crackme including keygen for fake name/serial (also keygen sources included). 2024-12-12 13:53 View
yum :P Bartam0us 2024-12-12 05:35 View
no-standards anon786 Cool CTF with some anti-debugging techniques... 2024-12-10 14:21 View
LSDtrip crackme! Benbaby Explain & keygen. 2024-12-10 13:58 View
Very hard challenge Benbaby Not very hard challenge 2024-12-08 17:30 View
LSDtrip crackme! aname reverse logic and write bruteforce python script using itertools 2024-12-07 12:35 View
Secret CrackMe Benbaby Nice and thanks! 2024-12-04 16:21 View
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