| BabyRev |
Slavetomints |
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2025-02-26 19:04 |
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| mihawkre |
Vanzen |
Pretty simple, "find the key in the code and plug it in" kind of problem. |
2025-02-17 00:18 |
View |
| BabyRev |
Aotrix |
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2025-02-16 00:50 |
View |
| Password-cmd |
Vanzen |
Not a super clear success state, fairly certain I did this right though. Write-up attached. |
2025-02-15 23:14 |
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| Switching crackme |
Snxhit |
Detailed overview, with keygen and decompiled source inside :) |
2025-02-15 18:47 |
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| .net_crackme_no.1 by subminking |
Vanzen |
Nice easy one, text writeup including a small program attached. |
2025-02-14 22:42 |
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| Beginner |
slither |
(Recommended for beginners and their first crack with DNSpy)check solution.txt
|
2025-02-14 00:35 |
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| Sexy 1337 |
SaHHiiLL |
includes a keygen.c |
2025-02-13 13:20 |
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| easy keyg3nme |
Snxhit |
This crackme is fairly simple, it just checks for to see if the entered key is divisible by 1223. I also made a three line python script to output a random key which will work, since I didn't know how exactly this was to be keygen'd.
It is a good crackme for beginners to the world of reverse engineering such as myself. Had fun, thanks Ezman! |
2025-02-12 19:03 |
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| easy_reverse |
fieldhamster |
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2025-02-11 23:42 |
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| BabyRev |
Sanca |
tehee |
2025-02-05 19:00 |
View |
| easy_reverse |
Sanca |
my first crackmes problem |
2025-02-05 18:34 |
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| VeryEasyCrackme |
ver02 |
I opened the executable in IDA Free and inspected the main function, where I found that the password was in plaintext and was hardcoded as "YourPass".
The program performs two anti-debugging checks: CheckDebug() uses IsDebuggerPresent() to detect a debugger, and CheckDebug2() checks for a debugger via an IAT function. To bypass these checks, I modified the RIP value to skip over both functions and prevent the program from calling ExitProcess().
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2025-02-04 07:19 |
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| first crakme xor |
Koalko |
The password length in the program is constant and equals 8. After entering the password, the program goes through the password 3 times, using XOR encryption (xorEncryptDecrypt) with the values 75, 76 and 77. It is easy to calculate that 75^76^77 = 74. The calculateChecksum function returns the sum of the ASCII values of the characters in the string. Therefore, to build the password, we need to find values such that when XORed with 74 and subtracted from 300, they will be multiples of 7 (since the original password length is 8, and now we are calculating the index of the first value). Once we find the first value of the password, we can calculate the next character and repeat it 7 times.
To calculate the next character, we keep temporary variables for convenience. Let A be the missing sum for the checksum, then A = 300 - (index ^ 74). Let B be the XOR value of the required character. Since we need to fill 7 characters and A is a multiple of 7, then B = A / 7. So the required character index is B^74. The general formula is:
(300 - (i^74)) / 7) ^ 74 |
2025-01-31 00:04 |
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| Insanely Simple CrackMe |
CreHx |
I used Hex Editor and simply looked into the exe
I selected the text I thought was the correct password, I was right |
2025-01-26 09:21 |
View |
| EZ crackme |
zaer777 |
simple challenge to warm up |
2025-01-20 23:17 |
View |
| crack me funny lvl 2 |
Benbaby |
Explaination. It's really good for starting static analysis. |
2025-01-18 16:34 |
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| crypted string crackme |
Pau1CTFer |
Dynamic analysis techniques |
2025-01-18 07:00 |
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| Rose.exe |
CZ-DannyK |
Monster solution for this amazing crackme. |
2025-01-17 21:18 |
View |
| Winforms License key Validation crackme |
framekop |
Goal, How IT work, Solution. Everthing in the PDF file. |
2025-01-12 15:55 |
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| Easy Crackme |
Benbaby |
It's OK. Explaination is attached. |
2025-01-11 15:15 |
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| Baby Keygen 2 |
jhosuakz |
Thanks |
2025-01-10 15:21 |
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| CrazyCrackMe |
jmpeax |
Explanation and keygen |
2025-01-07 19:20 |
View |
| Simple Keygen |
carougeno |
Solution in a .txt (Cutter) |
2025-01-06 15:11 |
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| CrackMe OS | Part 1 |
Benbaby |
Thanks Lxwxrs. It's good. Including explaination and source code. |
2025-01-05 15:51 |
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| CrYP70NYM'S CRACKME FIXED |
Benbaby |
I hate random. Explaination & source code. |
2025-01-05 04:37 |
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| LoginCrackme |
Benbaby |
It's OK. Explaination and code. Thanks Bros. |
2025-01-03 17:31 |
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| pAsSwoRD_GO |
Andrysqui |
A solution to this CrackMe by decompiling/disassembling the code and inspecting it to crack the password as it's only encoded, plus explanations to everything. |
2025-01-01 18:45 |
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| Hard work bro |
Tut |
Download the solution |
2025-01-01 12:43 |
View |
| zun1 crackme |
bernas198YT |
I hope you understand my explanation |
2024-12-31 19:14 |
View |
| mihawkre |
wepinek |
Simple dnSpy knowledge |
2024-12-31 10:06 |
View |
| StillAching's CrackMe |
Adb2 |
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2024-12-29 09:38 |
View |
| nasm crack |
Shun |
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2024-12-27 16:24 |
View |
| guess_the_password |
Shun |
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2024-12-27 15:28 |
View |
| zuha crackme |
Benbaby |
Explain how to do. Thanks ChatGPT told me such ideal. |
2024-12-25 16:16 |
View |
| SecretKeyCrackme |
Benbaby |
Explaination and script. |
2024-12-25 14:52 |
View |
| Fatmike's Crackme #2 |
Benbaby |
LSD crackme. But absolutelly good. Including explain and source code of keygen. |
2024-12-22 18:22 |
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| my first crackme |
Benbaby |
Explain & source code of keygen. Thanks |
2024-12-22 04:38 |
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| Sexy 1337 |
vsalce01 |
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2024-12-16 05:55 |
View |
| Plain sight |
fuzzybear |
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2024-12-14 21:46 |
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| Find password |
ax4w |
very nice, explanation, solution and c code in the file. |
2024-12-13 20:04 |
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| TryCrackMe |
ax4w |
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2024-12-13 18:52 |
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| TryCrackMe (v1) |
Benbaby |
Note and source code of keygen. It’s OK. Clear encrypt function and easy to follow. |
2024-12-13 17:06 |
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| Fatmike's Crackme #6 |
CZ-DannyK |
Solution for this crackme including keygen for fake name/serial (also keygen sources included). |
2024-12-12 13:53 |
View |
| yum :P |
Bartam0us |
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2024-12-12 05:35 |
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| no-standards |
anon786 |
Cool CTF with some anti-debugging techniques... |
2024-12-10 14:21 |
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| LSDtrip crackme! |
Benbaby |
Explain & keygen. |
2024-12-10 13:58 |
View |
| Very hard challenge |
Benbaby |
Not very hard challenge |
2024-12-08 17:30 |
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| LSDtrip crackme! |
aname |
reverse logic and write bruteforce python script using itertools |
2024-12-07 12:35 |
View |
| Secret CrackMe |
Benbaby |
Nice and thanks! |
2024-12-04 16:21 |
View |