crackmes.one

Latest Solutions Latest activity RSS

Crackme Author Summary Date Action
Hidden MessageBox Tricta Write-Up of qbit32's Hidden MessageBox with two solution methods 2023-10-18 02:23 View
Level1 21021420 A highly detailed solution with decompiled source, even newbies can understand :) 2023-10-17 14:59 View
Level1 p4tched Thanks for the crackme! This is a simple explanation based on a decompiled view of the program. 2023-10-15 16:39 View
License Checker 0x02 xxdave 2023-10-08 16:43 View
Level1 xxdave 2023-10-08 16:37 View
based jacblo i solved it without brute forcing. 2023-10-04 13:47 View
pavler3 moval0x1 0x0 - The Theory You need to bypass all the obfuscated parts. After that, you will find here the validate function: 00401816 | 55 | push ebp You need to skip a little more of the whole obfuscated code and then you'll see the validation If the user typed had lowercase char 00401D38 | 803C0A 61 | cmp byte ptr ds:[edx+ecx],61 00401D8E | 803C0A 7A | cmp byte ptr ds:[edx+ecx],7A It should be increased by one 00401E12 | FEC0 | inc al If the user typed has an uppercase char 00401E62 | 803C0A 41 | cmp byte ptr ds:[edx+ecx],41 00401EB2 | 803C0A 5A | cmp byte ptr ds:[edx+ecx],5A It should be decreased by one 00401F3C | FEC8 | dec al As it only accepts letters, it will only work for a range from aA-zZ. 0x1 - Valid User x Pass User name:movalzeroxone Password?:npwbm{fspypof Correct! 0x2 - Keygen Here is my keygen ;) user = input("Type your username: ") generated_password = "" for x in user: if ord(x) = 65 and ord(x) 2023-10-03 02:18 View
super_easy amnam Decompile using Ghidra and a sample flag. 2023-09-29 19:21 View
License Checker 0x02 amnam Crack it using the 'strings' command, and then decompile and analyze the code using Ghidra. 2023-09-29 09:35 View
hexagon solardev solution :) 2023-09-29 08:59 View
PleaseCrackMe 0chabyte First timing GDB 2023-09-26 19:32 View
based bang1338 A writeup of my process and solution. In zip file contain: - Bunch of image instead hosted on Discord - a markdown, which is my writeup and solution. Require a GitHub-like markdown reader like Markdown Monster - A Python script to solve, require Python 3.x - A decompiled source code of luna crackme (C++, recommend gcc) Side note: gg cnathansmith 2023-09-26 13:21 View
GPTCrackMe cnathansmith Complete walk-through with keygen 2023-09-25 17:59 View
Secret message from a traveller cnathansmith Long writeup is loooooong. But there's a lot to cover and we look at all of it. 2023-09-24 21:14 View
hexagon I3a4dam Not an expert solution but it gets the job done. 2023-09-24 12:10 View
cracknkeygen amnam Solution + Code to generate keys 2023-09-21 13:17 View
gugus the first amnam A simple text file and an explanation of what I did to solve it. :)) 2023-09-21 11:43 View
licesnse_checker_3 amnam I used Ghidra to generate code and then performed some cleaning up. 2023-09-21 09:58 View
my_f1rs7_cr4ckm3 amnam Easy solution :)) 2023-09-21 08:12 View
find a real key amnam Disassemble using Ghidra and write a C code to generate the key. 2023-09-21 07:39 View
hexagon cnathansmith Simple walkthrough and keygen 2023-09-21 04:07 View
EasyCrackMe:) d0x75 Key : 12345 Attached is a summary of the validation + crackme solution in file 2023-09-19 12:25 View
Freemasonry bang1338 A writeup of my process and solution. In zip file contain: - Bunch of image instead hosted on Discord - a markdown, which is my writeup and solution. Require a GitHub-like markdown reader like Markdown Monster - A Python script to solve, require Python 3.x 2023-09-17 13:31 View
Freemasonry cnathansmith Simple walkthrough using dnSpy 2023-09-17 11:16 View
EAX-Crackme cnathansmith Simple walkthrough, with api_log tool included for easily finding API calls 2023-09-17 10:46 View
based cnathansmith Walkthrough and keygen source code implementing the atypical approach of converting the target into a shared library to directly interface with program functions externally 2023-09-17 08:14 View
snake cnathansmith Full walk-through with source for solver 2023-09-16 17:50 View
TinyCrackMe Yanderome 2023-09-14: smol solution 2023-09-14 19:05 View
encrypted_box cnathansmith Full walk-through with custom tool source needed to solve 2023-09-14 04:35 View
C# Login-Crackme by #BeginnerCracker123 cnathansmith Simple walkthrough 2023-09-13 14:03 View
heaven.exe cnathansmith Full walkthrough and solution 2023-09-09 12:33 View
Crackme -.NET kajalkatiyar Solution of Crackme.net by reading code. 2023-09-05 16:28 View
Mexican kajalkatiyar Obtain flag just by looking at the code :) 2023-09-05 16:08 View
timotei crackme#7 Lorvillian Text explain and solution. 2023-09-01 14:27 View
Find password adi7312 2023-08-31 15:47 View
get the password Jenya i wrote explanations in read_me file 2023-08-29 22:10 View
Beginner Friendly Crack-Me kill_your_soul Easy crackme for beginners. I like to solve this 2023-08-29 21:43 View
Salty's Easy Key Software unitythecoder the C Keygen. Thanks to Ghidra 2023-08-28 18:03 View
crackme4 by arjani ToMKoL Solution with patch (+src). 2023-08-24 13:51 View
Level1 rawbit the solution is in the attached text file 2023-08-23 20:05 View
Keygen Practice Frauweigel My python function also gives a key with the size of 9. It only searches for characters between a-z A-Z and 0-9. If it finds a ascii value that is equal to 650 it prints the key. 650 because 650 * 9 * 9 = 52650 (checksum) 2023-08-21 22:12 View
cracknkeygen rawbit 2023-08-20 17:55 View
timotei crackme#11 1K-Edition :-) cnathansmith Walkthrough with keygen and searches for interesting messages that can be produced. 2023-08-18 23:24 View
My First Crack Me elpe_pinillo 2023-08-18 20:56 View
keygencrackme_1 by zyen sa2304 2023-08-18 11:37 View
angry file Lorvillian Constraint solving using angr 2023-08-18 10:40 View
FindMe elpe_pinillo 2023-08-18 08:30 View
Auth Pin bang1338 A writeup of my process and solution. In zip file contain: - Bunch of image instead hosted on Discord - a markdown, which is my writeup and solution. Require a GitHub-like markdown reader like Markdown Monster - A semi-deobfuscated version of this crackme. 2023-08-17 07:51 View
FindMe bang1338 A writeup of my process and solution. In 7z file contain: - Bunch of image instead hosted on Discord - a markdown, which is my writeup and solution. Require a GitHub-like markdown reader like Markdown Monster - Python script for solution, require Python 3.x 2023-08-16 14:31 View
find a real key RJ I've provided a detailed analysis on the binary and a python script to generate the flag. 2023-08-16 09:38 View
Previous Page 30 Next