juansacco on 7:57 AM 11/30/2022: + ------------------- +
| Find the Password 1 |
| by Xeeven |
+ ------------------- +
Password: 8675309
+ *** *** *** *** *** +
| Congratulations! |
+ *** *** *** *** *** +
alwani on 11:41 PM 12/04/2022: I really appreciate that you included the source code with usefull comments. Thank u.
The password can be obtained by using strings command.
amr.asmr on 9:53 AM 12/24/2022: I cracked it twice by gdb and strings.
In gdb way I add breakpoint at [jecxz] instruction ,so when gdb hit the breakpoint I set ecx to 0