| 00007FF72C5D2A2C | 74 2D | je ctf_level6.7FF72C5D2A5B | we set the breakpoint and then change the zf from 1 to 0 |
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| this is really hard i cant find solution but i find password maybe 50 symbols, and ebp-140 and ebp-150 maybe work with password |
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| Great crackme! The use of C++ STL vectors and bitwise operations added a nice layer of complexity, making the reverse-engineering process engaging. The "matrix" theme and AI-related functions (AI::generate_matrix, AI::calculate_score) were intriguing, though their lack of impact on the final result slightly reduced their significance. Including a unique pattern or additional constraints could enhance the challenge. Overall, well-crafted and fun to solve!
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| Отличная идея! Использование C++ STL-векторов и побитовых операций добавило дополнительный уровень сложности, сделав процесс обратного проектирования увлекательным. Тема "матрица" и функции, связанные с искусственным интеллектом (AI::generate_matrix, AI::calculate_score), были интригующими, хотя отсутствие их влияния на конечный результат несколько снижало их значимость. Включение уникального шаблона или дополнительных ограничений могло бы усложнить задачу. В целом, все хорошо продумано и решать его интересно! |
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| Great crackme challenge! The logic was clear, and the use of XOR and arithmetic checks made it engaging. Including sub_140001EE0 added a nice layer of complexity. A hint about case sensitivity would improve clarity. Thanks for the fun reverse engineering task!
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| how do I open your file? |
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