| Sorry my original comment broke idk why. The crackme was fun and thanks for making it. for the username Expl0it- the key is :;@AC |
3:07 AM 04/25/2021 |
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| Username: Expl0it-
Key: :;@AC |
3:04 AM 04/25/2021 |
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| Awesome crackme! I was able to reconstruct the algorithm and make a keygen which provides a valid key for any username entered. |
8:23 PM 04/17/2021 |
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| Awesome crackme! It took me a few days on and off to figure out because I am a beginner but I learned a lot about bitwise operations. The key I came up with was c8e&4 |
2:55 PM 04/16/2021 |
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| Thanks for the crackme. It was my first substitution cipher I have solved as I am a beginner. I submitted a writeup and I am waiting for it to be approved. |
12:15 AM 04/10/2021 |
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| I am a beginner and this was my first level 2 crackme. I was able to see the decrypted password and username by putting a breakpoint on the test that determines if the password is 17 characters or not.
The password is: $2833-15431-51KEY
The username is: crck_me |
2:38 AM 04/07/2021 |
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