mohammadali's crackme_you

Author:
mohammadali

Language:
C/C++

Upload:
2021-02-22 10:59

Download

Platform:
Windows

Difficulty:
3.0

Quality:
3.5

Arch:
x86

Downloads:
15

Size:
75.60 KB

Writeups:
2

Comments:
7

Description

hii everyone, this is a nice easy challenge, it is so simple: you need to write a keygen to crack it ... i hope you enjoy it

Comments (7)
Writeups (2)

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4epuxa on 2021-03-07 08:20: Hello. Crackme is pretty easy because I didn't even have to make a keygen. Why did this happen? Because my entered password does not "mutate", it changes. That is, I just need to enter the password, which should be in ecx. sub ecx, eax We need it to be zero. In ecx, our password, and in eax, the password is generated. In my case, the generated password will be AEE4C0F0. That is, it is -1360740112. Everything, crackme is solved.

mohammadali on 2021-03-08 04:06: @4epuxa i know you can solve it without making a keygen, and you can understand nothing from the program and yet be able to solve it, the fun part is in understanding what are you doing and having fun reversing not just dumping ecx for the password... read the last paragraph from the faq anyways good job reversing it , im cooking something else you may not be able to reverse it

MrNatas on 2021-04-17 20:23: Awesome crackme! I was able to reconstruct the algorithm and make a keygen which provides a valid key for any username entered.

ZombieCheats on 2021-04-28 03:52: This was the best crack me every I love this so much it took me like 50 secs to crack but I love it ;) this helps a lot learning

uj4 on 2024-12-07 19:45: decompiled the crfcaewxsed func, took the dump and put it in vs, changing a few things and passing the username i want in: keygenned = v2 ^ (v2 * (*(DWORD*)usernameInput - v2) - v3 + 70595907 + v2 * (*(DWORD*)usernameInput - v2));

Bala on 2025-10-24 07:41: Hi. What is the password for unzipping the sample?

Bala on 2025-10-24 07:43: Ya i got it

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Solution by pranav on 2021-03-11 04:15:
Hey! Genuinely it was fun! Your algorithm was little confusing, but when I put time into it, it was solvable. This is my first comprehensive writeup, so I hope you respond with the feedback! SideNote: The writeup is compressed, because it was too big for my internet connection to handle

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Solution by Danielix on 2021-04-03 18:29:
i found that in your main you were checking username with the result of the function "crfcaewxsed(str)", simply that function is itself the keygen

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crackmes.one

crackmes.one

mohammadali's crackme_you_sh**t v2