indigo on 2019-01-03 23:40:
To me as a beginner, this was just about the right difficulty. Could probably even be difficulty 1. Definitely fun!
s4r on 2019-01-04 08:44:
I modified the difficulty, thanks for the feedback
Tritone on 2019-01-08 17:30:
This was a lot of fun as a beginner. Thanks!
mosh on 2019-01-11 13:00:
really enjoy it, thank you
ekalien on 2019-01-14 12:28:
anybody knows what's the password?
mosh on 2019-01-15 17:32:
@ekalien you have solutions on the right
Gifroy on 2019-01-27 13:18:
Alright, finally solved it! This was my very first crackme. It took me a good 5 hours to solve but I learned a lot of basics in the progress (including researching x86 assembly, debugging tools etc). Thanks!
zer0sun on 2019-02-03 04:45:
1212121212121212
长度是16个字符串，并且从offset 0开始的每2个字符串差1
tanmaybhushan on 2019-02-12 20:11:
*c = char of Rand(0-100)
len = 0
while len
tanmaybhushan on 2019-02-12 20:12:
[Click to reveal]Increment of previous character and length of 16, no place to upload solution.
cIsForCookies on 2019-02-14 22:46:
Nice one! was my first try at a crackme and took me about an hour to get a good serial, though I haven't cracked it entirely. Anyway, it was a lot of fun, Thx!
cmasterisk on 2019-02-16 09:27:
[Click to reveal]./SimpleKeyGen $(python -c 'print "AB"*8')
wirehack7 on 2019-02-24 19:12:
What is the password of the archive? It's missing in description
tenghaooo on 2019-03-07 11:54:
Who wants to know what the password is, please read FAQ first
Foxar on 2019-04-04 15:43:
Quick and easy, perfect for beginners.
Example serial codes:
abababababababab
bcbcbcbcbcbcbcbc
cdcdcdcdcdcdcdcd
dededededededede
efefefefefefefef
Sn0kr45h on 2019-04-30 02:10:
Thanks for the good puzzle Yuri. It took me about 3 hours to figure out the algorithm without looking at answers. Sometimes the disassemblers make some really funky code, but with debugging and observation the answer becomes pretty apparent with patience. Writing a keygen that works with it was also quite fun and simple.
oscar on 2019-06-01 15:40:
Very fun, enjoyed trying to understand the serial checking algorithm. Wish I hadn't read the comments as they kind of spoil it.
ttotons on 2020-05-07 20:59:
It was really awesome and fun. This is actually my first crack me. It took me about 25min to get to the right serial keys. Thank you a lot. As this is my first solve I feel very good and happy.:) Btw I used "ghidra" to crack this.
trizas on 2020-09-22 08:17:
import string
import random
import time
import os
while True:
chars = string.ascii_letters
key = ""
for i in range(8):
c1 = random.choice(chars)
c2 = chr(ord(c1) + 1)
key += c1 + c2
print(key)
cmd = "./SimpleKeyGen " + key
os.system(cmd)
time.sleep(2)
trizas on 2020-09-22 08:18:
THX Yuri, so good for a begginer, very funny =)
Solution by TheChrississin on 2020-05-19 21:41: Solved using Ghidra and keygen is written in Java.
Zip includes screenshots of Ghidra and output, .java file, the binary and a writeup.