you need to know what the little-endian and big-endian are and when they are used.
The solution is
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21401 not 04121 |
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if ( !strcmp(String, valid_license) ), the value of the valid license is dynamic not fixed, it will change every time you will restart the execution of the program. Find strcmp function in x32dbg.
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I reversed the generate_license function. It generates a random key based on the time of the machine in seconds, right?
Any hint, please |
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solution:
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user: a
serial is: f
take 'a' and get ASCII '65' and xor with 4
and add 1 then get the char of the result
result= (65^4)=69
result+=1
result=70 // f in ASCII |
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Here is my writeup for this crackme:
https://youtu.be/omG-W2GMem4 |
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Here is my writeup for this crackme:
https://youtu.be/kh74ZISnw0A |
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Here is my writeup for this crackme
https://youtu.be/3ublxMr7pg4 |
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Here is the writeup for this crack
https://youtu.be/RBxRCzNaOPk |
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you are wasting time with this kind of crackmes |
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Here is my writeup for this crackme
https://youtu.be/yJWxE7XKD_8 |
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beginner friendly |
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*Here is the writeup for the crackme
https://youtu.be/0dL9FKze4cw |
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Here is the writeup for the crackme
https://youtu.be/FrnLTSeeH_A |
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can someone make a writeup for this crackme? |
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here is the writeup for this crackme
https://youtu.be/FrnLTSeeH_A |
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.NET crackme |
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not easy but nice |
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it's packed, so how is it level 1? |
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nice one |
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that was funny |
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https://github.com/eleemosynator/writeups/blob/master/white_rabbit/readme.md |
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This is definitely not level one |
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I didn't understand the solution?
and what does this %4[^\n] mean? |
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i can't crack thsi |
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