| CrackMe4 |
nice solutions guys. Well done! |
2026-01-24 17:27 |
| KeyGenMeV3 |
Well Done! SenorGPT a very detailed explanation 👍🏻 |
2025-12-13 16:02 |
| KeyGenMeV3 |
@patbateman. Well written tutorial thanks for sharing and Well Done! 👍🏻 |
2025-11-30 06:09 |
| KeyGenMeV3 |
@fakesiva. No! but at least you are learning 👍🏻 |
2025-11-30 05:55 |
| KeyGenMeV3 |
genass3 Well Done! 👍🏻 |
2025-11-30 05:54 |
| KeyGenMeV3 |
Well Done! dimkasi2 👍🏻 |
2025-11-23 08:01 |
| funcoleto |
make a text file called "gameHack" in Documents and put. this text inside it "0x90-HACKEADO-0x90". :) nice crackme |
2025-10-12 17:32 |
| Pie |
import hashlib
import string
def md5_hex_upper(s: str) - str:
return hashlib.md5(s.encode("utf-8")).hexdigest().upper()
def build_serial(name: str, prefix6: str) - str:
if len(prefix6) != 6 or any(ch not in string.printable[:-6] for ch in prefix6):
raise ValueError("prefix6 must be exactly 6 printable ASCII chars")
mid7 = md5_hex_upper(name)[:7]
return prefix6 + mid7 + "FBC"
if __name__ == "__main__":
name = input("Enter name: ").strip()
prefix = "KRACK-"
try:
serial = build_serial(name, prefix)
print("Your Serial is:", serial)
except ValueError as e:
print("Error:", e)
|
2025-10-12 12:26 |
| Pie |
For name = “Coder”
MD5("Coder") (UTF-8, uppercase hex) = 14C0F98E06BCD735D89C0C6A57488CCD
First 7 hex chars = 14C0F98
Therefore, any valid serial for “Coder” must be:
FBC
KRACK-14C0F98FBC :)
|
2025-10-12 11:55 |
| KeyGen APP |
nice! |
2025-08-09 22:08 |
| KeyGen APP |
nice try :) the goal is to make a keygen for it :) |
2025-08-09 20:46 |
| Impossible(ish) CrackMe challenge V2 |
awesome123 is the password :) |
2025-08-09 18:08 |
| Impossible(ish) CrackMe challenge V2 |
admin
123456 :)) |
2025-08-09 17:30 |
| Easy, but interesting for novice |
easi123 |
2025-08-09 17:13 |
| keygenme90 |
I might post a recoded one this one has some flaws :/ |
2025-08-04 15:44 |