_int2eh's VeryEasyCrackme

Author:
_int2eh

Language:
C/C++

Upload:
2024-10-28 05:29

Download

Platform:
Windows

Difficulty:
1.2

Quality:
2.7

Arch:
x86-64

Downloads:
44

Size:
1.16 MB

Writeups:
2

Comments:
16

Description

This crackme will be great for you who are beginners in reverse engineering. It's very simple

Comments (16)
Writeups (2)

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korsader on 2024-10-31 06:13: Sua senha esta correta.Thanks

Tragos on 2024-11-01 16:21: This was, as you said, really easy. Wrote a simple write-up for it and even decompiled it. https://github.com/johnnnathan/Crack/tree/main/VeryEasyCrackme_by_int2eh

alxxx on 2024-11-02 10:09: sha256{eb19200c4d5cdd529b4344ea16b3a45a00ae3c5cc1a62e7f66e0b29bcf13abf0}

Kafiw on 2024-11-03 19:29: [Click to reveal]

SirWardrake on 2024-11-05 00:51: since the password is in plain text, Xor encryption is pointless

samfhritp on 2024-11-07 14:36: very easy, but nontheless good for beginners :)

abobafoba on 2024-11-19 16:15: why does this shit close right away?

0xe1 on 2024-11-30 12:10: Digite a senha: thx, it's my first crack) Sua senha esta correta

IBOGRO on 2024-12-08 14:17: The problem was ok , and the password for the ZIP file it's "crackmes.one".

WOYH12 on 2025-01-14 13:29: It closes right away in x64dbg but it could be solved when you install anti-anti debug plugin(ScyllaHide). It was very easy to crack but I don't know how to get password to be printed out instead of password error message.

bernas198YT on 2025-01-16 16:58: [Click to reveal]

RAJ on 2025-01-19 08:45: as a starter it was easy. I used ghidra to understand

0x_x0 on 2025-02-15 00:44:

0x_x0 on 2025-02-15 00:45: alert(1)

snowdev on 2025-02-23 15:32: very easy just used jmp to the correct

TeRrArIsT on 2025-08-08 15:58: [Click to reveal]

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Solution by brutus on 2024-11-07 14:35:

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Solution by ver02 on 2025-02-04 07:19:
I opened the executable in IDA Free and inspected the main function, where I found that the password was in plaintext and was hardcoded as "YourPass". The program performs two anti-debugging checks: CheckDebug() uses IsDebuggerPresent() to detect a debugger, and CheckDebug2() checks for a debugger via an IAT function. To bypass these checks, I modified the RIP value to skip over both functions and prevent the program from calling ExitProcess().

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