Author:
RainerZimmerman

Language:
C/C++

Upload:
2023-03-04 20:38

Download

Platform:
Unix/linux etc.

Difficulty:
2.7

Quality:
4.2

Arch:
x86-64

Downloads:
4

Writeups:
3

Comments:
7

Description

Pretty simple key checking algorithm, reverse it and generate a key for it - There exists many valid keys.

• Comments (7)
• Writeups (3)

You must be logged in to post a comment

RainerZimmerman on 2023-03-08 00:37: Just realized there is a very easy solution I forgot to remove! If you find it, please ignore it. :)

strawberry_cake on 2023-04-07 19:16: 000-000000000

RedVi on 2023-06-22 10:13: Thx For Fun Challenge 000-000000000

RedVi on 2023-06-24 01:12: nice challenge flag: flag{_y0u_f0und_key_} python script: first = [0x51,0x53,0x4E,0x11,0x50,0x3D,0x51,0x11,0x41,0x50,0x11,0x52,0x3D,0x49,0x11,0x57,0x3D,0x0F,0x11,0x11,0x15] second = [0x37,0x3F,0x2F,0x76,0x2B,0x62,0x28,0x21,0x34,0x0F,0x77,0x62,0x48,0x27,0x75,0x8,0x56,0x6A,0x68,0x4E,0x68] for i in range(0,len(first)): print(chr(first[i] ^ second[i]),end="")

driftxmaster on 2023-07-31 19:49: very nice challenge, it was fun

v0da on 2023-08-01 09:04: there is also another small bug. 000-000999981 is valid where 9+9+9+8+1 = 45 , also 000-999990000 etc

SirWardrake on 2024-05-22 00:49: nice challenge. Wrote a little keygen 474-616889418 124-324579122

You must be logged in to submit a writeup