RedXen's Ultimatum CrackMe

Author:
RedXen

Language:
C/C++

Upload:
2021-12-06 17:55

Download

Platform:
Windows

Difficulty:
1.2

Quality:
2.9

Arch:
x86

Downloads:
10

Writeups:
1

Comments:
31

Description

A simple crack me written in C/C++. It is not hard, but you must retrieve the original key and not patch the file! If you find it, please comment the key and submit your solution. Have fun!

Comments (31)
Writeups (1)

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bl4ack on 2021-12-10 23:38: [Click to reveal]

TrollZik on 2021-12-11 08:38: The code seemed really obsfucated, but at the end the password was just declared in rdata

NoMercy on 2021-12-11 16:57: [Click to reveal]

Erpreet on 2021-12-11 22:00: [Click to reveal]

nassimorg09 on 2021-12-15 21:51: [Click to reveal]

sophie1p on 2021-12-16 01:08: [Click to reveal]

pirik3 on 2021-12-16 23:47: [Click to reveal]

KPia on 2021-12-17 03:41: Strings: LCMapStringEx 0123456789abcdefghijklmnopqrstuvwxyz 0123456789abcdefghijklmnopqrstuvwxyz bad exception Interesting but I don't have Windows Rn

iDONTKNOWHO on 2021-12-17 20:23: What the key for extract ??

Sidd_Tim on 2021-12-19 17:17: [Click to reveal]

Genzen on 2021-12-21 05:52: I like the fact you hid an Easter egg in the password lol

SirLez on 2021-12-22 19:34: Well done! Please sumbit a solution on the crackmes.one website under this post!

martifix1337 on 2021-12-23 16:11: rdata:0042988C VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh found in strings

0xZF on 2021-12-29 05:55: [Click to reveal]

kiyo0216 on 2022-01-01 19:42: Used strings and found VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh

MrForce on 2022-01-02 00:05: VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh

Cecilio on 2022-01-02 01:42: VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh Just defined in the .rdata segment

OutTuna on 2022-01-07 08:23: thx for good CrackMe software) VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh

auth1337 on 2022-01-09 23:15: [Click to reveal]

Shelldon on 2022-01-12 09:42: [Click to reveal]

Texugo on 2022-01-20 15:10: [Click to reveal]

Bipin on 2022-02-09 17:18: [Click to reveal]

sickfunk on 2022-02-16 05:55: [Click to reveal]

Ftor7 on 2022-03-20 09:42: [Click to reveal]

Rot4tion on 2022-04-03 12:31: [Click to reveal]

sz_skill on 2022-04-28 04:16: Looks really "advanced" but it's just hardcoded like any other. Replace je/jne call (i forgot) at 00402190 to jmp 0x402260

Kutch on 2022-04-28 12:44: [Click to reveal]

xnf4o on 2022-06-02 07:48: [Click to reveal]

0x02 on 2022-06-27 17:31: [Click to reveal]

Dola123312 on 2022-07-03 18:19: [Click to reveal]

coutooo on 2025-09-03 18:57: " This is the correct passkey, well done! "

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Solution by 7cherubin on 2021-12-28 11:48:
Simply step through the program until a bunch of comparisons are performed at which point it is revealed that the password has been hardcoded in plain text and compared in an obfuscated (?) way against the user's input. *Password: VGhpcyBpcyB0aGUgY29ycmVjdCBwYXNza2V5LCB3ZWxsIGRvbmUh*

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