Marquire's CrackMe_V4

Author:
Marquire

Language:
C/C++

Upload:
2021-09-27 21:02

Download

Platform:
Windows

Difficulty:
2.8

Quality:
4.0

Arch:
x86

Downloads:
22

Size:
10.50 KB

Writeups:
3

Comments:
17

Description

This is the successor of CrackMe_V3_Marquire with an increased 'security' for the hidden key. The goal would be to find the right key.

Comments (17)
Writeups (3)

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ra1n1ng on 2021-09-30 16:38: Good upgrade since the last I managed to get XCJUPIBSCDQ, sadly this is wrong, I don't have time to reverse this right now so if someone could write a solution that would be great!

ra1n1ng on 2021-09-30 17:19: [Click to reveal]

Marquire on 2021-09-30 17:22: [Click to reveal]

ra1n1ng on 2021-09-30 18:03: Thank you, just sent a solution btw for others. Hope to see a v5 soon!

DispatchCode on 2021-10-01 09:37: @Marquire: you said that there are different solutions... so a key (without any meaning) that pass the validation test, is valid? :P

DispatchCode on 2021-10-01 09:56: ...as an example the key: GE?LBEOZJ?ZWD is considered valid or a not intended solution?

ra1n1ng on 2021-10-01 13:11: @DispatchCode From what I've seen, it's to do with the encryption and hashing that allows for different keys to work

DispatchCode on 2021-10-01 14:17: Yeah, but so what I ask is: there is just a valid or preferred/accepted key, or N valid keys? Yesterday I have looking into it and I have written a little C code that generate multiple keys. So I'm just asking if "random" keys (but with the same hashing values) are valid or not :)

Marquire on 2021-10-01 14:18: Every key which is accepted is right then :) but this was not intended

DispatchCode on 2021-10-01 14:23: @Marquire: Ok, thanks for the clarifications :) May I give a suggestion? Next time maybe you can give the key format so there are no doubt about it. ;) Anyway, good crackme/keygenme!

Marquire on 2021-10-08 14:52: I have uploaded a V5 version a couple of days ago.. But it seems to take some time here.

ra1n1ng on 2021-10-08 17:31: @Marquire can't wait for a v5, I too uploaded a solution for v4 however It too seems to be taking some time.

ra1n1ng on 2021-10-14 22:47: I don't think anything is being uploaded...

1337ReverseEngineer on 2022-07-23 22:36: Very nice crackme.

WorcCrow on 2022-10-04 03:04: https://github.com/WorcCrow/CrackMeEP0004/blob/master/Solution%20CrackMe%20V4.js real nice challenge

Tomutt on 2025-08-07 13:14: I can't solve it. I looked up other's writeups as well but I still don't get it. The workflow is : user input key - encoding(00402160-0040218f) - reference integers checksum(004023c0-004023d6) - encoded user input key checksum(004023e3-004023fa).. so the point is 'how to find a sequence of 'encoded user input key(integers)' that satisfies both the reference checksum when it goes through checksum logic, and being within ASCII range when it's reverse-encoded. While, the reference checksum is the result of checksum calc that is run with 32 integers.

Tomutt on 2025-08-07 13:34: 13 reference integers, i mean

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Solution by ra1n1ng on 2021-09-30 18:02:

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Solution by ThePhilosopher on 2021-10-19 14:28:
Thanks for the challenge

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Solution by g3chantr on 2022-01-11 17:37:
Thank's for this chall

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crackmes.one

crackmes.one

Marquire's CrackMe_V4_Marquire