Author: TLOD
Language: C/C++
Upload: 4:39 PM 05/10/2021
Platform Windows
Difficulty: 2.0
Quality: 3.5
Arch: x86
Description
This a little more advanced than the previous crackme. As before, only use numbers for the pass. Please create a keygen. Enjoy!
4epuxa on 6:20 PM 05/14/2021: login 4epuxa pass 13104 pass = login[3]*(login[2]+((login[4]*login[1])%(login[0]*login[5)))
TLOD on 9:09 PM 05/14/2021: Well done 4epuxa! However there is more behind the key generation. Maybe try out a different name ;)
Anhkhoa on 9:16 AM 05/16/2021: I have a bit of a problem, can you give me a solution to solve it?
TLOD on 2:12 PM 05/16/2021: Anhkhoa sure, dm me on discord: TLOD#0882
SirWardrake on 8:38 PM 03/06/2024: Nice one, not too hard
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Solution by dev0:Write up and a keygen C source file.
Solution by bmdyy:Python3 script which works for names which are 4 letters long. Nice easy challenge, thanks!
Solution by Exp0x8zf:Keygen in Python
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