Sir_Zed's Keygen Me Part 1

Author:
Sir_Zed

Language:
C/C++

Upload:
2021-02-23 12:17

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Platform:
Windows

Difficulty:
2.5

Quality:
6.0

Arch:
x86

Downloads:
14

Size:
11.26 KB

Writeups:
2

Comments:
20

Description

This is my first keygenme and i think its too easy to make a keygen. Make sure you read the first 6 lines in hint file first. Good Luck!

Comments (20)
Writeups (2)

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mohammadali on 2021-03-09 12:43: [Click to reveal]

4epuxa on 2021-03-09 14:11: Nice and interesting crackme, thank you so much for your work. The essence of generating the correct password: 1) We have a line: ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890 She acts as a kind of counter. 2) We also have hardcoded characters, which will be our password. Suppose for A, it is ".-". 3) The algorithm is as follows: First, we toupper () all our symbols. Then we get into a loop where we compare characters from a string with our username (see 1). Let's take that the table stores an already hardcoded password. i is a counter. variableForCountPassTable = 0; someString = "ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"; for (int i = 0; i

4epuxa on 2021-03-09 14:13: Then we get into a loop where we compare characters from a string with our username (see 1). Let's take that the table stores an already hardcoded password. i is a counter. variableForCountPassTable = 0; someString = "ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"; for (int i = 0; i

4epuxa on 2021-03-09 14:31: In general, for some reason the site does not want to correctly display my comment. I probably will sumbit a solution. There are a lot of interesting things

Sir_Zed on 2021-03-09 18:10: [Click to reveal]

Sir_Zed on 2021-03-09 18:13: @4epuxa Hi, Good job i think you made it! i think it would be great if you submit your solution with tutorial. GJ again!

ToMKoL on 2021-03-10 14:54: Judging by the charset I supose it's base36 conversion.

Sir_Zed on 2021-03-10 17:49: @ToMKoL I don't think so man :) take a look at the hint file!

4epuxa on 2021-03-10 20:01: solution submitted, waiting for verify

Sir_Zed on 2021-03-10 21:22: @4epuxa GJ, Be ready for the next part :)

pranav on 2021-03-11 04:59: Personal opinion ofc, but I think it should be L3 for the sole reason it's C++. It feels like searching for a tiny piece of gold in a whole river

Sir_Zed on 2021-03-11 08:42: @pranav i know what you mean, but as i said in hint file : "If i were you i wouldn't use IDA pro because its just make it harder :D the key validation algorithm is just 6 lines but in IDA pro its just too much and complicated."

pranav on 2021-03-12 16:40: I don't even have IDA pro

mohammadali on 2021-03-13 14:54: i patched it at : https://github.com/ORCA666/patched-files/tree/main/Sir_Zed's%20Keygen%20Me%20Part%201

noobvariable on 2021-05-11 16:07: it is not easy, thank you, it make me happy, solution i posted

Sir_Zed on 2021-05-14 06:10: @noobvariable Good job! Be ready for next part :)

Onyx_Pl01t on 2022-01-05 21:22: Very nice CrackMe. 1) No Patching: DONE 2) Keygen: DONE (in python) Tutorial: 1.It asks the user to enter a username. 2.The program 'uppercases' each character of the username 3.It takes each character of the uppercased-username and converts it to its specific morse code(hard-coded string) 3)Keygen: https://pastebin.com/eED2MzYv IMPORTANT: 1. I found an error in the program. When I enter a username: "abcdefghijklmnopqrstuvwxyz1234567890", the serial should be: ".- -... -.-. -.. . ..-. --. .... .. .--- -.- .-.. -- -. --- .--. --.- .-. ... - ..- ...- .-- -..- -.-- --.. .---- ..--- ...-- ....- ..... -.... --... ---.. ----. -----" but while debugging it, the program compares it with ".- -... -.-. -.. . ..-. --. .... .. .--- -.- .-.. -- -. --- .--. --.- .-. ... - ..- ...- .-- -..- -.-- --.. .---- ..--- ...-- ....- ..... -.... --... ---.. ----. -----" which is: "abcdefghijrlmnopqrstuvwxyz1234567890". the 'k' has been swapped with 'r'. I gave more details in my python script 2. I noticed that for any username less than 36, the serial is calculated at a certain length of words, That is, For username: OnyxPl01t, serial: ONYXPL01TUW2U(morse code converted into plain text). I am not understanding this part. It is adding additional characters to the username of length less than 36. Could you explain the logic behing this as i have been struggling +15 hours to understand this part. I am a beginner so, any hint would welcomed :). I am waiting for your next CrackMe sir!

morchik on 2022-05-26 16:19: Excellent

PhongNguyenQUang on 2023-05-29 09:26: .

jeffli6789 on 2026-01-04 06:25: This crackme had been reviewed when it was originally approved and is likely safe. Crackmes often get flagged by antivirus software, EDR systems, or VirusTotal because they may use the same protection techniques found in malware (packers, anti-debugging, self-modifying code, etc.), or simply a false positive. This does NOT mean the crackme is actually malicious. The only way to confirm whether something is truly malware is to reverse engineer it and find proof of malicious code and/or malicious behavior. If you still believe this is actual malware, please report it to us via email: crackmesone@gmail.com. **We encourage everyone to run crackmes in a VM (virtual machine) and exercise caution when executing unknown binaries.** *Disclaimer: We do our best to review submissions, but mistakes can happen. The administrators and crackmes.one cannot be held liable for any damages or losses resulting from the use of files downloaded from this site. Always exercise caution and use a sandboxed environment.*

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Solution by 4epuxa on 2021-03-10 20:01:

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Solution by noobvariable on 2021-05-11 16:08:
solution

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