Ultimation on 2019-01-09 15:58:
Finished - Keygen solution in c#
---- Code Begin -----
var key1 = 0;
var uname = Environment.UserName;
Console.Write("Enter name:");
var name = Console.ReadLine();
foreach (var c in uname)
{
key1 += (byte)c +100000;
}
foreach (var c in name)
{
key1 += (byte)c + 100000;
}
key1 += 0x7A69;
Console.WriteLine($"Key: {key1}");
------ Code End ------
K2000 on 2019-01-14 01:10:
[Click to reveal]Name: 1
Reg: 832122
K2000 on 2019-01-14 01:19:
Phemis , MrShy and juansacco have the wrong codes. Their codes are not working.
K2000 on 2019-01-14 01:48:
[Click to reveal]You can also try Name: aaaa RegNum: 1132461
mosh on 2019-01-15 17:11:
really enjoy it, thank you, i think it's probably level 2, as you can see most of the comments are wrong.
Anish on 2019-01-24 10:45:
[Click to reveal]Done not take much time i dont know how i did this but did :D
name :- 004D0590
Reg num :- 1732581
K2000 on 2019-01-26 03:25:
[Click to reveal]Anish , your registration number is not working. Try :
Name: 004D0590
RegNum: 1532495
gmy77 on 2019-01-28 14:07:
[Click to reveal]Username: gmy77
Reg.Num: 1032327
Easy to find... this crackme is a nice start.
Phemis on 2019-01-30 18:33:
K2000 tutorial video is here : https://phemisz.blogspot.com/2019/01/crackmec-tutorial.html
Phemis on 2019-01-30 19:00:
K2000, keygen is here: http://s2.dosya.tc/server6/7a3vk7/cilingir.exe.html
GUERRIEX on 2019-02-03 14:21:
whats the zip password ?
Phemis on 2019-02-03 16:40:
GUARRIEX read the faq.
reverflotz on 2019-02-15 19:52:
what is the password for the zip file ???
reverflotz on 2019-02-15 19:54:
Never mind I read the faq
madlogik on 2019-02-22 03:01:
[Click to reveal]Changing the push data from "Try Again" to the serial makes a bad try a keygen straight to the messagebox ;)
(In the try again change the push from : PUSH 405034 to: PUSH 19F744 )
madlogik
1232564
zaturion on 2019-02-26 18:28:
Hey guys, this was my first CrackMe I solved and I wondered about your comments because they are all wrong, or atleast partially wrong.
The solution is:
1. convert your Windows-Username to ASCII-Code, sum them up and add (X*100000) where X is the usernames length in characters.
2. Repeat Step 1. for the name you have chosen in the crackme.exe
3. Add both sums together and add "31337"
Thanks for the riddle, was really fun and took me some hours as I just began researching reversing :)
thoonline on 2019-03-08 15:12:
zaturion - agree with you.
TheBrokenWasp on 2019-06-11 19:33:
How come everybody make keygens? I mean I just found and removed the key cheek so I can type in anything I want :S
TheBrokenWasp on 2019-06-11 19:38:
Nevermind I just read the faq... Where would I find programs designed to be patched?