| password : 0xJam3z
这是代码中的异或
00007FF7987416D4 | 83F0 6D | xor eax,6D |
这是代码中的解密一个是正确结果一个是自己输入的结果
把正确结果的ASCII 异或6D后 查找ASCII表一个个输入出来 就是正确密码
00007FF798741708 | 48:8D55 C0 | lea rdx,qword ptr ss:[rbp-40] |
00007FF79874170C | 48:8D45 80 | lea rax,qword ptr ss:[rbp-80] |
This is the XOR in the code:
00007FF7987416D4 | 83F0 6D | xor eax,6D |
This is the decryption in the code, one is the correct result, and the other is the result of your own input
After putting the correct ASCII XCII XCII 6D, and finding the ASCII table, enter it one by one, and it is the correct password
00007FF798741708 | 48:8D55 C0 | lea rdx,qword ptr ss:[rbp-40] |
00007FF79874170C | 48:8D45 80 | lea rax,qword ptr ss:[rbp-80] |
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==> |