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| Name | Author | Language | Arch | Difficulty | Quality | Platform | Date | Downloads | Writeups | Comments |
|---|
| Crackme | Date | Infos | Actions |
|---|---|---|---|
| Tenzo Crack ME Beta | 2026-09-11 06:31 | Brute force solution | View |
| Patch Protect v3 | 2025-10-20 08:11 | solution in python | View |
| Patch protect lite | 2025-10-02 20:41 | View |
| Crackme | Difficulty | Points | Date |
|---|---|---|---|
| No flags submitted yet. | |||
| Crackme | Comment | Date |
|---|---|---|
| alpmira | [Click to reveal]SWAP_PAIRS = ((0, 4), (1, 5), (2, 6), (3, 7), (8, 12), (9, 13), (10, 14), (11, 15)) MIX_BLOCKS = ((0, 1, 2, 3, 7, 4), (8, 9, 10, 11, 15, 12)) CROSS_PAIRS = ((0, 8), (1, 9), (2, 10), (3, 11), (4, 12), (5, 13), (6, 14), (7, 15)) KEYS = ((0x6C, 0x51, 0xB7), (0x9F, 0x13, 0x35), (0x1A, 0x2B, 0xE3), (0xB7, 0xC7, 0x48), (0x35, 0x8E, 0x7D), (0xE3, 0xB2, 0x6C)) b1, b2 = [0] * 16, [0] * 16; b2[8] = 0x80 b3 = [0x65, 0x57, 0x0C, 0x1A, 0x65, 0x5C, 0x2A, 0x66, 0x40, 0x4F, 0xA2, 0xA2, 0xFB, 0xD2, 0x2F, 0x20] b4 = [0x50, 0xD1, 0x3E, 0x04, 0x59, 0x98, 0x60, 0xB2, 0xD2, 0x18, 0x40, 0x4F, 0x6F, 0xE2, 0x27, 0x49] b5 = [0x92, 0xFC, 0x22, 0xCA, 0x29, 0x80, 0xB4, 0xFB, 0xAB, 0x30, 0x61, 0x58, 0x7C, 0x1A, 0x74, 0xF7] b6 = [0x9D, 0x25, 0x07, 0x53, 0x49, 0x42, 0x39, 0xE7, 0x88, 0x7B, 0x11, 0xD2, 0xC9, 0x78, 0xD9, 0xC9] b8 = [0x4B, 0x53, 0x5F, 0x44, 0x30, 0x4D, 0x5F, 0x76, 0x36, 0x5F, 0x64, 0x6F, 0x6D, 0x5F, 0x73, 0x65] b9 = [0x4B, 0x53, 0x5F, 0x44, 0x31, 0x5F, 0x73, 0x65, 0x67, 0x5F, 0x30, 0x31, 0x5F, 0x61, 0x61, 0x00] b10= [0x4B, 0x53, 0x5F, 0x44, 0x32, 0x5F, 0x73, 0x65, 0x67, 0x5F, 0x30, 0x32, 0x5F, 0x62, 0x62, 0x00] enc_blocks = [ [0x42, 0x96, 0xE4, 0x25, 0x00, 0x77, 0x95, 0x21, 0xB9, 0xBE, 0x82, 0xD2, 0x5A, 0xA1, 0x86, 0xAB], [0x97, 0xFA, 0xB7, 0xEC, 0x95, 0x35, 0x60, 0x3C, 0x36, 0x33, 0xD8, 0x61, 0x32, 0x8F, 0xBB, 0xA6], [0x79, 0xB8, 0x03, 0xED, 0xFC, 0xF9, 0x45, 0x2E, 0xA6, 0x1A, 0xA2, 0x4B, 0x3D, 0x96, 0x4A, 0x2A], [0x49, 0x17, 0x9B, 0x10, 0x65, 0x29, 0xFE, 0xC1, 0xA1, 0x49, 0x0D, 0x88, 0x25, 0x55, 0x67, 0x21], [0x7A, 0x53, 0xB5, 0xC7, 0x84, 0xEB, 0x91, 0xC9, 0xF7, 0x2B, 0xDD, 0xEE, 0xDD, 0x48, 0x05, 0x98], [0xFA, 0x47, 0x05, 0x7E, 0xFA, 0x07, 0xDA, 0x3C, 0x0B, 0x8C, 0xB8, 0xF3, 0x3F, 0x25, 0x64, 0x4F], [0x02, 0x02, 0xFB, 0xC4, 0x55, 0x70, 0xE1, 0xEB, 0x43, 0xC1, 0xBA, 0x51, 0xCC, 0x66, 0x10, 0x37], [0x2A, 0x4D, 0x5B, 0x06, 0x2B, 0x54, 0x98, 0x1E, 0xAE, 0x07, 0xC8, 0x43, 0x5F, 0x46, 0x85, 0xCA], [0xEB, 0x16, 0x94, 0x3D, 0x55, 0xE5, 0x62, 0x5A, 0xEE, 0xF2, 0x2C, 0xB3, 0xCE, 0x9F, 0xAB, 0x50], ] def rol8(x, n): return ((x << (n & 7)) | (x >> (8 - (n & 7)))) & 0xFF def transform(block, state=None): s = list(state) if state is not None else [0] * 16 for i in range(16): s[i] ^= block[i] for k0, k1, k2 in KEYS: for a, b in SWAP_PAIRS: s[a], s[b] = s[b], s[a] for a, b, c, d, off_c, off_d in MIX_BLOCKS: s[a] = rol8((s[a] + s[b]) & 0xFF, s[b]) ^ k0 s[b] = rol8((s[b] + s[off_c]) & 0xFF, s[c]) s[c] = rol8((s[c] - s[d]) & 0xFF, s[d]) ^ k1 s[d] = rol8((s[d] + s[c]) & 0xFF, s[off_d]) ^ k2 for a, b in CROSS_PAIRS: s[b] = rol8(s[b], s[a]) s[a] = rol8(s[a], s[b]) return s def hx(data): return " ".join(f"{x:02X}" for x in data) def clean_txt(b_data): return "".join(chr(x) if 32 <= x <= 126 else "." for x in b_data) def decrypt(key): b0 = list(key.encode('ascii')) if len(key) == 16 else list(bytearray(key.encode('ascii')) + b'\x80' + b'\x00' * (15 - len(key))) state = None for _ in range(3000): state = transform(b0, state) state = transform(b1, state) state = transform(b2, state) b0 = state state = None for b in (b3, b4, b5, b6, b0, b1, b2): state = transform(b, state) b7 = state decoded_blocks = [] enc_iter = iter(enc_blocks) for group_header in (b8, b9, b10): state = transform(group_header, b7) state = transform(b7, state) state = transform(b7, state) for i in range(3): if i > 0: state = transform(b7, state) decoded_blocks.append(bytes(e ^ s for e, s in zip(next(enc_iter), state))) return decoded_blocks if __name__ == "__main__": key = "12345" result = decrypt(key) print("\n".join(f"{hx(b)} | {clean_txt(b)}" for b in result)) # Python Script | 2026-09-21 20:38 |
| alpmira | [Click to reveal]I understand there can be no solution? | 2026-09-21 20:36 |
| ZSecure | [Click to reveal]FLAG: Z+{1tS_JU5t_SImulation} | 2026-09-13 08:56 |
| custom vmp crackme | So did you need to find the flag? The task says to find the password | 2026-09-13 07:15 |
| Easiest | [Click to reveal]pass: 8569 MOV EAX, DWORD PTR SS:[RBP-4] CMP EAX, 0x2179 | 2025-11-03 17:53 |
| Simple_GUI_crackme | sorry, above post is in the wrong place | 2025-11-03 17:52 |
| Simple_GUI_crackme | [Click to reveal]pass: 8569 MOV EAX, DWORD PTR SS:[RBP-4] CMP EAX, 0x2179 | 2025-11-03 17:50 |
| C++ idk | [Click to reveal]pass: 4v9cbr217 | 2025-10-30 08:26 |
| 3OutOf6 | [Click to reveal]pass: 68 | 2025-10-30 08:06 |
| MasonCrackmeV2 | [Click to reveal]pass: MEMSENALF difficulty: very easy | 2025-10-30 07:35 |
| c/c++ Crackme | [Click to reveal]any string of 32 lenght symbol will be valid, for example: lexxlexxlexxlexxlexxlexxlexxlexx | 2025-10-28 19:06 |
| Assembler Crackme | [Click to reveal]pass: @CBEDGFI | 2025-10-26 14:00 |
| .NET AoT + Anti debug Checks | [Click to reveal]pass: sex ??? | 2025-10-26 04:30 |
| Patch Protect v3 | [Click to reveal]pass: DEADBEAFDEADBEEFDEADBEEFDEADBEEF | 2025-10-20 08:00 |
| simple crackme medium-hard | [Click to reveal]pass: TotallySecureKey123 | 2025-10-07 11:52 |
| Impossible PatchingMe | [Click to reveal]license: lexx status: ok code: 3GMD4XLY2P5CGAXEGMYNQIIRT5W4EQ2T7SMBRNXXVOGVHOKYX7JQ | 2025-10-04 21:55 |
| Impossible PatchingMe | Hi And what should happen after entering the correct or incorrect password? The program freezes after the output "code:". | 2025-10-03 21:26 |
| MISSION IMPOSSIBLE | [Click to reveal]3f39999999999999, it was easy | 2025-10-02 21:45 |
| easiest crackme | requires a library, but can be disassembled without them using static analysis: int main { void var_140; char const* const var_30; std::cout var_140; if(var_140 == "verysecret69"){ var_30 = "Access denied!"; } else { var_30 = "Access granted!"; } return 0; } | 2025-07-06 20:23 |
| makeKEYgen | [Click to reveal] Enter username: ghhghhggh Enter password: BE34A10D | 2025-06-26 17:14 |
| Ransomware | [Click to reveal]F4N_N3R0{W3lc0m3_t0_my_pr0f1l3_7h1s_1s_my_w@ll3t_k3y} Good puzzle :) | 2025-06-26 10:02 |
| Anti_Debug | Is the flag in hexadecimal form? In the string it is not read. hex result: 06 0A 0A 19 1E 09 1D 0A 58 23 0B 04 56 2A 46 1A 89 CE A0 9B 54 0C 1A 5E 0A 2A 09 6D 7B 21 21 7D | 2025-06-25 14:08 |
| Hard | It is quite easily located with the help of Cheat Engine, the password lies next to the introduced value in memory, if the password were removed from the memory, it would be more difficult | 2025-06-18 17:15 |