Number of crackmes:
Number of writeups:
Comments:
| Name | Author | Language | Arch | Difficulty | Quality | Platform | Date | Downloads | Writeups | Comments |
|---|---|---|---|---|---|---|---|---|---|---|
| Easy Crackme For Beginners | kotsuge | C/C++ | x86-64 | 3.2 | 4.0 | Windows | 2026-06-25 03:51 | 728 | 0 | 12 |
| Crackme | Date | Infos | Actions |
|---|
| Crackme | Comment | Date |
|---|---|---|
| XOR Challenge By 0xbadc0de | [Click to reveal]password: mr1337 sub_1400173D0 this is the xor sub. sub_140017CD0 this is the main sub. | 2026-07-26 11:05 |
| Ultimate Boss Level - Final | [Click to reveal]def generate_crackme_inputs(username: str): v5 = sum(ord(c) for c in username) v108 = 31 * v5 v107 = (v108 ^ 0x1337) + 123 decryption_key = v107 ^ 0x3E return { "String Key (v112)": username, "Integer 1 (v108)": v108, "Integer 2 (v107)": v107, "Decryption Key Byte": decryption_key & 0xFF } print(generate_crackme_inputs("admin")) THE ULTIMATE LICENSE CHECK Enter Username: admin Enter Part 1: 16151 Enter Part 2: 11419 [+] Access Granted! [+] Message: ┤îö├Üîû├çèç├èù┬ Press Enter to exit... | 2026-07-23 19:29 |
| Level 10 | ============================= CRACKME LEVEL 10 (BOSS) ============================= Enter Password: aNtidisEsTABLisHmenTarIAN [+] Correct! Decrypted flag: Perfect! Press Enter to exit... that was easy what is this 10 lvl... | 2026-07-21 21:43 |
| Level 9 | [Click to reveal]lrys'ume | 2026-07-21 21:39 |
| Level 8 | [Click to reveal]============================= CRACKME LEVEL 8 ============================= __int64 sub_140001070() { _OWORD *v0; // rax __int128 v2; // [rsp+20h] [rbp-40h] __int128 v3; // [rsp+30h] [rbp-30h] _BYTE v4[22]; // [rsp+40h] [rbp-20h] *(_QWORD *)&v2 = 0x7F03001202000001LL; *((_QWORD *)&v2 + 1) = 0x300340200010100LL; *(_QWORD *)&v3 = 0x56020002010055LL; *((_QWORD *)&v3 + 1) = 0x7802000301002203LL; *(_QWORD *)v4 = 0x2000401000A0300LL; *(_QWORD *)&v4[8] = 0x50100F9030090LL; *(_DWORD *)&v4[16] = 50379778; *(_WORD *)&v4[20] = 196; v0 = (_OWORD *)sub_140002140(Size: 0x36u); xmmword_140006230 = v0; qword_140006240 = (__int64)v0 + 54; *v0 = v2; v0[1] = v3; qmemcpy(v0 + 2, v4, 22); *(&xmmword_140006230 + 1) = (char *)v0 + 54; return sub_1400023C0(Function: sub_140003220); } Enter 6-Letter Password: matrix [+] Correct! Decrypted flag: Yu`f}l5 Press Enter to exit... | 2026-07-21 21:33 |
| Level 7 | [Click to reveal]__int64 sub_140001000() { _DWORD *v0; // rax v0 = (_DWORD *)sub_1400022C0(Size: 7u); Block = v0; qword_140007240 = (__int64)v0 + 7; *v0 = 1060713270; *((_WORD *)v0 + 2) = 10548; *((_BYTE *)v0 + 6) = 63; *(&Block + 1) = (char *)v0 + 7; return sub_140002540(Function: Function); } license | 2026-07-21 21:30 |
| Level 6 | [Click to reveal]============================= CRACKME LEVEL 6 ============================= Enter 5-Letter Key: crack [+] Correct! Decrypted flag: Pj``ffg" Press Enter to exit... | 2026-07-21 21:26 |
| Level 5 | Part1 % 17 == 0 ve Part2 (Part1 ^ 0x1337) + 42 | 2026-07-21 21:22 |
| Level 4 | [Click to reveal]def generate_level4_serial(username: str) -> int: total = 0 for char in username: val = ord(char) if val > 127: val -= 256 total += val serial = (123 * total) & 0xFFFFFFFF return serial user = "admin" print(f"Username : {user}") print(f"Serial Key : {generate_level4_serial(user)}") | 2026-07-21 21:19 |
| Level 3 | [Click to reveal]def generate_serial(username: str) -> int: total = 0 for char in username: val = ord(char) if val > 127: val -= 256 total += val multiplied = (1337 * total) & 0xFFFFFFFF serial = multiplied ^ 0x5A5A return serial if __name__ == "__main__": user = "admin" key = generate_serial(user) print(f"Username : {user}") print(f"Serial Key : {key}") | 2026-07-21 21:16 |
| Level 2 | [Click to reveal]__int64 sub_140001000() { _DWORD *v0; // rax v0 = (_DWORD *)sub_140001CB0(Size: 7u); Block = v0; qword_140005228 = (__int64)v0 + 7; *v0 = 1059864360; *((_WORD *)v0 + 2) = 10536; *((_BYTE *)v0 + 6) = 63; *(&Block + 1) = (char *)v0 + 7; return sub_140001F30(Function: Function); } this sub just give the key | 2026-07-21 21:02 |
| Secret key | [Click to reveal]C:\Users\utkui\Desktop\X64-Release>C:\Users\utkui\Desktop\code.exe Enter Your Number : 33 Enter The Secret Key : 102 Congratulations, you have completed the challenge! Good. | 2026-07-03 11:28 |
| IMGUI test auth | [Click to reveal]i patched it by looking to "sub_140053BB0" bcs key check is here all invalid key or auth strings are here you are checking the hosts file if there is your auths link you just decline the key but if i patch the "loc_14005466B" there is "xor bl, bl" and if i assemble it to "mov bl, 1" it just accepts the key good crackme btw | 2026-06-26 10:39 |
| cantcrack | [Click to reveal]0000000000001891:48->EB 0000000000001892:8D->D9 obfuscate your strings bro | 2026-06-26 10:15 |
| Easy Crackme For Beginners | [Click to reveal]btw the real password was "======================================== kotsugeINT3 kolay crackme ======================================== Enter Key: babapiroreversermisinya [+] helal bro. Press any key to continue . . ." but that was just my fault. | 2026-06-26 10:06 |
| Easy Crackme For Beginners | [Click to reveal]@dandelion_msla Yes, the key you sent is being accepted; this wasn't the original key, but that was entirely my fault. | 2026-06-26 10:04 |
| Easy Crackme For Beginners | @Ploxied I just realized I made a mistake in my custom VM; it accepts some 23-character passwords. I'll fix it next time. | 2026-06-26 10:03 |
| Easy Crackme For Beginners | @Ploxied oh sorry im gonna fix it btw key is not valid😔 | 2026-06-25 21:43 |
| Monsignors Crackme | [Click to reveal]secret... | 2026-06-25 02:57 |
| password esasy | [Click to reveal]umm 1234 | 2026-06-23 11:36 |