| found no anti-debugging features |
11:35 AM 02/09/2025 |
==> |
| solved using breakpoints |
10:28 AM 10/24/2024 |
==> |
| password is username + "-hqghumea"
Enter your username: iwn
Enter your serial key: iwn-hqghumea
Correct! Good job :D |
10:24 AM 10/24/2024 |
==> |
| keygen
import string, random
chars, key = string.ascii_letters + string.digits, ""
for i in range(11): key += random.choice(chars)
key = 'A' + key[0:2] + 'X' + key[4:7] + "X" + key[8:]
print(key) |
9:35 AM 10/24/2024 |
==> |
| This is the criteria for correct keys:
if ( (unsigned int)strlen(var2) == 11 )
{
if ( *var2 == 65 && var2[3] == 88 && var2[7] == 88 )
{
printf("The key entered is valid");
return 1i64;
}
as long as you have those, you have a correct key |
9:20 AM 10/24/2024 |
==> |
| take a look at this compiled code to find out the valid format:
if ( (unsigned int)strlen(localkey) == 11 )
{
if ( *localkey == 65 && localkey[3] == 45 && localkey[7] == 45 )
{ |
10:25 AM 10/23/2024 |
==> |
| keygen
import string, random
chars, key = string.ascii_letters + string.digits, ""
for i in range(random.randint(4, 9)): key += random.choice(chars)
key = 't' + key[1:4] + '-' + key[5:]
print(key) |
10:04 AM 10/23/2024 |
==> |
| SPOILER
else if ( user_input[0] == 116 && user_input[4] == 45 )
figured they were ascii characters. found it and the first character had to be a 't' and the fifth a hyphen. |
9:46 AM 10/23/2024 |
==> |
| user: iwn
serial: 5134153
cracked :) |
5:31 AM 10/18/2024 |
==> |
| user: iwn
key: 89 |
10:57 AM 10/17/2024 |
==> |
| https://i.imgur.com/xLYizkj.png
cracked |
9:53 AM 10/10/2024 |
==> |
| fill with NOPs |
9:17 AM 10/09/2024 |
==> |
| just saying, this got detected by antiviruses and virustotal |
10:50 PM 10/07/2024 |
==> |
| cracked, but what is it supposed to print if u returned a valid password? just "Welcome !" or is there anything else? |
10:38 AM 10/07/2024 |
==> |
| just search strings |
10:30 AM 10/07/2024 |
==> |
| K4FlAXxF4LZ |
12:57 AM 10/06/2024 |
==> |