| 1stCrackme |
dbuser
esi=02265418 "resubdresubdresubd"
|
2022-11-04 15:58 |
| Challenge #1 |
[Click to reveal]ThatWasEasy!
|
2022-11-04 15:32 |
| Crackme_with_GUI |
[Click to reveal]001F1998 68 E0381F00 push CrackMe.001F38E0 ; UNICODE "VcsE~oHYo7&f.CCJ)dU1pwRJ&FXu{pq~
|
2022-08-08 02:25 |
| CrackMe_EaminX |
[Click to reveal]passwd:Eamin
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2022-07-29 10:26 |
| Python CrackMe |
[Click to reveal]Pass = 'YouSuccCracked'
|
2022-07-29 08:33 |
| CrackMes 1.0 |
if ( !(unsigned __int8)sub_402370(v43, Block) ) cout
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2022-05-18 08:10 |
| CrackMes 1.0 |
Oh, my God, the answers keep appearing again during the debugging process, and I underestimated the length of password. It makes Ben look very simple. It becomes very complex. Oh, N0, consolidate the foundation and analyze the basic process of the program. It is divided into three judgments
if ( !(unsigned __int8)sub_402370(v43, Block) )
{
cout
|
2022-05-18 08:08 |