Number of crackmes:
Number of writeups:
Comments:
| Name | Author | Language | Arch | Difficulty | Quality | Platform | Date | Downloads | Writeups | Comments |
|---|
| Crackme | Date | Infos | Actions |
|---|
| Crackme | Comment | Date |
|---|---|---|
| 0x8A7 - Vault | FLAG{0x8A7_C4N4RY_L34K_4ND_R3US3} | 2026-07-18 18:09 |
| ComputeTheKey | X_SECRET_KEY_X_1307 i use angr to solve it | 2026-07-18 08:04 |
| DebugMe | DebugMe ) LD_PRELOAD=./override_fopen.so ./DebugMe 1 DebugMe stage 1: Pass DebugMe stage 2: Pass DebugMe stage 3: Pass Well done :) DebugMe ) | 2026-07-10 14:25 |
| seer | seer ) ./seer Have you already seen the future and come aware of the passphrase? yes What is the magical passphrase? awd Correct! seer ) | 2026-07-09 14:24 |
| good girl | good_girl ) ./good-girl 1 2 3 4 5 6 7 8 | 2026-07-09 14:11 |
| notes | notes ) ./note_writer password123 password: 123 note: troihomnaymua new note created! notes ) cat password123 ���s�m�j�f�p�y�⏎ notes ) ./run password123 troihomnaymua notes ) | 2026-07-09 09:42 |
| Sexy 1337 | Sexy_1337 ) ./sexy1337.out Enter the password: vh{|466: Access Granted! | 2026-07-08 15:08 |
| Password And Flag in C | Password_And_Flag_in_C ) ./senha-e-flag-C-2 Insira sua senha: senhafoda1234567890 Aqui está sua flag: HOWO{REVERSING-A-COMPLEX-XOR} Password_And_Flag_in_C ) | 2026-07-08 09:10 |
| Getting started keygen | Getting_started_keygen ) ./getting_started_keygen Enter a string of characters (no spaces): awdafawf Enter correct number (no spaces): 1087 OMG! You did it! :3 | 2026-07-07 17:18 |
| Cortisol level low keygen | Valid Key Found: 10004389054 Valid Key Found: 10004389061 Valid Key Found: 10004389078 Valid Key Found: 10004389085 Valid Key Found: 10004389092 Valid Key Found: 10004389108 etc | 2026-07-07 16:54 |
| BiLoop Cipher | biloop_cipher ) ./BiLoop_Cipher Username: admin123 Password: xdtgj1#3 Access Status: Success biloop_cipher ) good,thank you so much! | 2026-07-06 20:11 |
| Maths | Hint: Identify the hidden Fibonacci sequence modulo $1000000007$ in the obfuscated floating-point operations. Then, reverse-engineer the logic to find a prime Fibonacci triplet that satisfies Fermat's Last Theorem format | 2026-07-06 19:47 |
| Maths | assets ) ./maths Welcome a board !!! Developed by Binary Newbie Enter 4 numbers in a row: 3 4 5 1 Valid assets ) | 2026-07-06 19:36 |
| math_crackme | math_crackme ) ./main enter first number: 10 enter second number:2 CORRECT | 2026-07-06 18:56 |
| Accsess me please :) | 47029 | 2026-07-01 18:55 |
| a Treasure | bb{easy_r3v_challenge_s0lv3d} | 2026-07-01 18:49 |
| selfkey | Key 0x01 (1): xFo|k`Fjmkvw~Fixjjnvk},). Key 0x04 (4): }CjyneCohnsr{Cl}ooksnx),+ Key 0x05 (5): |BkxodBniorszBm|nnjroy(-* Key 0x07 (7): ~@izmf@lkmpqx@o~llhpm{*/( Key 0x0A (10): sMdw`kMaf`}|uMbsaae}`v'"% Key 0x0B (11): rLevajL`ga|}tLcr``d|aw&#$ Key 0x0C (12): uKbqfmKg`f{zsKduggc{fp!$# Key 0x0D (13): tJcpglJfagz{rJetffbzgq %" Key 0x0E (14): wI`sdoIebdyxqIfweeaydr#&! Key 0x0F (15): vHarenHdcexypHgvdd`xes"' Key 0x12 (18): kU|oxsUy~xedmUzkyy}exn?:= Key 0x16 (22): oQxk|wQ}z|a`iQ~o}}ya|j;>9 Key 0x18 (24): a_very_strong_password507 Key 0x19 (25): `^wdsx^rusnof^q`rrvnse416 Key 0x1A (26): c]tgp{]qvpmle]rcqqumpf725 Key 0x1B (27): b\ufqz\pwqlmd\sbpptlqg634 Key 0x1C (28): e[rav}[wpvkjc[tewwskv`143 Key 0x1D (29): dZs`w|ZvqwjkbZudvvrjwa052 Key 0x1F (31): fXqbu~Xtsuhi`Xwfttphuc270 | 2026-07-01 11:20 |
| Level1 | import angr import claripy def solve(): filename = "./level1" project = angr.Project(filename, auto_load_libs=True) flag_length = 64 flag_chars = [claripy.BVS(f"char_{i}", 8) for i in range(flag_length)] flag = claripy.Concat(*flag_chars) state = project.factory.entry_state(stdin=flag) for char in flag_chars: state.solver.add(char >= 0x20) state.solver.add(char <= 0x7e) simgr = project.factory.simulation_manager(state) simgr.explore(find=lambda s: b"You are correct :)" in s.posix.dumps(1)) if simgr.found: solution_state = simgr.found[0] # Lấy kết quả từ stdin và decode sang string cho dễ đọc result = solution_state.posix.dumps(0) print(f"[+] Flag tìm được: {result.decode('utf-8').strip()}") else: print("[-] Không tìm thấy đường dẫn hợp lệ.") if __name__ == "__main__": solve() | 2026-03-31 15:48 |
| ez crackme | ez_crackme ) ./crack AA correct password!!!⏎ | 2026-03-25 15:49 |
| Mind the Stack | mind_the_stack ) ./crackme Enter Username: qUANG Enter password for: qUANG FACE Access Granted | 2026-03-25 11:47 |
| fence | flag{railfence_cyphers_are_bad_} | 2026-03-25 11:14 |
| Type Punning | z+{7yp3_Punn1n9} it is right sir | 2026-03-23 13:50 |
| hexagon | sanemy@sanemy ~/D/c/hexagon> ./2 Enter serial code: 32543465456 [+] Correct password!⏎ | 2026-03-22 09:37 |
| Find the Flag | 11 + 32*i | 2026-03-22 04:32 |
| Level1 | sudo0x18 | 2026-03-21 14:08 |
| Find password | CTF{Gh1Dr4-4nD-5Tr4C3-15-H31L} | 2026-03-21 13:49 |
| Sh4ll1 | sanemy@sanemy ~/D/c/Sh4ll1 [126]> ./crackMe1.bin Password: q Good password | 2026-03-21 11:38 |
| yum :P | sanemy@sanemy ~/D/c/yum> ./yum Welcome mate, enter the password :D q Success! | 2026-03-21 11:24 |
| based | sanemy@sanemy ~/D/c/based> ./luna q Enter password, plz: a Welcome! using patch in ghidra!! | 2026-03-21 09:42 |
| Bingus | ./bingus pp | 2026-03-21 09:23 |
| X-0-R | CTFLearn{y0u_Y80r3d_th3_c0d3} | 2026-03-21 04:56 |
| ZEXOR-v1(Linux version) | AEXORRBSHA36325S33 | 2026-03-21 04:39 |
| Introduction to RE | 7Wtyr | 2026-03-20 05:31 |
| Introduction to RE | 7Wtyr | 2026-03-20 05:29 |
| CrackIt;) | CTF{My_S3cr3t_Fl4g}W0WY0uF0undM3{0r N0t} | 2026-03-18 18:43 |
| Quite a simple crackme | @!#-3~&,$;7?/.:%42+` | 2026-03-18 18:28 |
| really easy | iloveicecream | 2026-03-18 15:54 |