| CrYP70NYM'S CRACKME FIXED |
Solved !!!
Notes:
1. Wrote a Keygen which is basically a Memory Hack found the pointer address that points to the key and prints the value.
2. Wrote the keygen in python |
2024-08-14 11:10 |
| Insanely Simple CrackMe |
Solved !!!
Note: Passsword is in the file itself |
2024-08-12 08:11 |
| a little more difficult |
Solved !!!
Notes: Just set debug on a count |
2024-08-12 08:06 |
| a simple crackme using dll |
Solved!!!
Just reverse the checkPassword Function and don't take the rabbithole |
2024-08-11 15:09 |
| Easy to crack |
Solved!!! |
2024-08-11 14:36 |
| Simple Passcode |
First Timers Hint:
1. Use DnSpy to reverse the code.
2. Carefully check the check Function.
3. Use the same key to get the key and complete the challenge.
4. All the keys posted are wrong you will have a different everytime you execute the program.
My passcode was : BE2951310ED24D8E23CEA09862AEB161723F246B607742E25722C92AF746FB1F33D9243DDF333FCDCD29F771DFFF439EDB45280F9F053F996D44590859868A0C |
2024-08-11 14:02 |
| VaultCrackme |
Hint: The program uses a simple algorithm which increments the seed to be equal to secert (Secert can be found in the binary itself).
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2024-08-11 09:23 |