Number of crackmes:
Number of writeups:
Comments:
| Name | Author | Language | Arch | Difficulty | Quality | Platform | Date | Downloads | Writeups | Comments |
|---|
| Crackme | Date | Infos | Actions |
|---|
| Crackme | Comment | Date |
|---|---|---|
| off_by_one | [Click to reveal]Passphrase: DXUPWYfU Yes! You found the correct passphrase ヽ(・∀・)ﾉ | 2026-08-06 12:22 |
| Just In Time | [Click to reveal]Password is %djk(9^}.f@1F4 | 2026-08-06 11:56 |
| learn for begineer | [Click to reveal] ./easy_find_text 1 只要中文 2 i want english > 2 --- easy step 1 --- hint just find text in binary enter pass kali you find it good job ./mid_math_xor 1 中文 2 english > 2 --- mid mode 2 --- find part 1 as text but part 2 is xor 0x42 math enter pass 1 kali enter pass 2 777 very good you find it part 2 is 777 import time from pwn import * # Start the binary process p = process('./hard_mem_rip') # Select option 2 (English) p.sendlineafter(b'> ', b'2') # Instantly calculate the current key current_time_block = int(time.time()) // 10 key = f"kali_secret_{current_time_block}_key".encode() log.info(f"Sending key: {key.decode()}") # Send Pass 1 (the dynamic key) p.sendlineafter(b'enter key fast', key) # Print whatever the binary responds with (won/loose) print(p.recvall().decode()) python a.py [+] Starting local process './hard_mem_rip': pid 142189 [*] Sending key: kali_secret_178549727_key [+] Receiving all data: Done (53B) [*] Process './hard_mem_rip' stopped with exit code 0 (pid 142189) very amazing you capture it from memory you are god | 2026-07-31 11:28 |
| Password And Flag in C | [Click to reveal]./senha-e-flag-C-2 Insira sua senha: senhafoda1234567890 Aqui está sua flag: HOWO{REVERSING-A-COMPLEX-XOR} | 2026-07-31 11:01 |
| TryHard crackme with password | [Click to reveal]Password: rootaccess1337 FLAG: CRACKME{MULT1_P4TH_D3R1V4T10N_12_L4Y3RS_VM_D3C0Y_PWND} | 2026-07-31 10:39 |
| simple XOR crackme | [Click to reveal]./crackme 'ABC&E@GH98K51NOP' | 2026-07-25 15:44 |
| Demian's entry level crackme | [Click to reveal]Directly found via strings: sw0rdf1sh | 2026-07-22 05:57 |
| dailycracking_by_flipflop by flipflop | [Click to reveal]Password : Crack+date e.g. Today is 22/07/2026 so password Crack22 | 2026-07-22 05:54 |
| nasm crack | [Click to reveal]Password : "supersecret" you can see in the ghidra 0x00402026 | 2026-07-22 05:04 |
| FirstCrackMe | [Click to reveal]simba123 you can find it in strings | 2026-07-22 04:59 |
| Getting started keygen | [Click to reveal]./getting_started_keygen Enter a string of characters (no spaces): aaaaaa Enter correct number (no spaces): 758 OMG! You did it! :3 Use GDB and Ghidra to debug put breakpoint at local_7c == iVar1 | 2026-07-22 04:11 |
| simples by imp | [Click to reveal]Debug the application you can find application opens port 31279 so you can connect it via telnet > open 127.0.0.1 31279 And challenge is solved | 2026-07-21 15:12 |
| Secret key | [Click to reveal]Use ghidra and you can see hex value where i compares digit and there you can find solution 33 and 102 | 2026-07-21 14:58 |
| catgirl.crack | [Click to reveal]In CatgirlCrack.dll you will found "mint" as your password | 2026-07-21 04:03 |
| GetToKnow-v0.1 | [Click to reveal]Put the debugger in x64dbg and you will find value on breakpoint of cmp assembly instruction Solution : 1mN0TTh3PwTru5tM3 | 2026-07-21 03:57 |
| My First CrackMe | [Click to reveal]in .dll file you will find string "password" which is password | 2026-07-21 03:50 |
| Easy crackme | [Click to reveal]Characters that ARE divisible by 4 (Count toward your 4 required) Numbers: 0 (ASCII 48), 4 (ASCII 52), 8 (ASCII 56)Uppercase Letters: D (68), H (72), L (76), P (80), T (84), X (88) Lowercase Letters: d (100), h (104), l (108), p (112), t (116), x (120) Demo Key: KEY048D111 | 2026-07-21 03:32 |
| ACrack | [Click to reveal]Nickname : CrackMeOne Password : t.me/Umno223 You can get them via strings finding | 2026-07-21 03:16 |
| ZEXOR-v1(Linux version) | [Click to reveal]Key founded in valid(), click UH to see the value of UH when it was strcmp : AEXORRBSHA36325S33 | 2026-07-21 03:08 |
| Fixed Easy Crackme | [Click to reveal] EasyPassword | 2026-07-21 02:55 |
| very easy crack me $$$ by whekkees | [Click to reveal]Login : whekkes Password : qwerty | 2026-07-21 02:55 |
| Monsignors Crackme | [Click to reveal]Password : secret | 2026-07-21 02:54 |
| really easy | [Click to reveal]iloveicecream | 2026-07-21 02:54 |
| password esasy | [Click to reveal]Digit: 1234 | 2026-07-21 02:54 |