Author:
BananaGrease

Language:
C/C++

Upload:
9:56 AM 11/11/2024

Download

Platform
Windows

Difficulty:
2.6

Quality:
3.0

Arch:
x86

Description

Ok so here's the idea, I was rather impressed with how well my last one was solved so I have tried to make something unique to pose a challenge. The source code is already posted but to not ruin the fun, the password to the paste bin is the secret message. You should find the message really quickly but still, it's more fun if you solve it yourself first. c++ src: https://pastebin.com/4iub2wFq

• Comments
• Solutions

kvfs on 4:25 PM 11/26/2024: the password i could get in the PE seems not to be the correct one for the pastebin (bqhpzrvlllllllll) am i close with that password or i'm completly wrong?

kvfs on 4:29 PM 11/26/2024: i also got this one without patching any bytes but also says incorrect password fywswwsuyxpekkkk

ichigone on 4:25 AM 12/05/2024: Setting a breakpoint before your entered license key and generated password are compared will allow you to read the password generated based on your name in plaintext. Entering my username, the password is cnsbkjacvuodbdlc. This is stored in ebp. There is also the string "Heres_A_Secret" stored at FE4330 in memory. This changes the success message and tells you that you are a clever clogs. I also received this message when forcing entry by changing 3 je's to jmp's

Zero09 on 3:04 AM 12/10/2024: I'm not a dumbass,password is very easy to find but ı don't want to deal with Password was calculate this sh*ts: var_3C= dword ptr -3Ch = 120 Block= dword ptr -38h = 112 var_28= dword ptr -28h = 80 var_24= dword ptr -24h = 72 var_20= dword ptr -20h = 64 var_1C= dword ptr -1Ch = 56 var_18= dword ptr -18h = 48 var_14= byte ptr -14h = -20 var_10= dword ptr -10h = 32 var_C= dword ptr -0Ch = 24 var_4= dword ptr -4 = 8 Src = dword ptr 8 = 16 arg_4= dword ptr 0Ch = 24 arg_10= dword ptr 18h = 48 arg_14= dword ptr 1Ch = 56 _DWORD var_3C; = 240 void *Block; = unvalid _DWORD var_28; = 160 _DWORD var_24; = 144 int var_20; = 64 _DWORD var_1C; = 112 _DWORD var_18; = 96 char var_14[4]; = 0000 0020 = 0 _DWORD var_10; = 64 _DWORD var_C; = 48 _DWORD var_4; = 16 _DWORD __saved_registers; _UNKNOWN *__return_address; void *Src; = geçersiz int arg_4; = 24 int arg_10; = 48 int arg_14; = 56

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