danyad29011's crackme lel

Author:
danyad29011

Language:
C/C++

Upload:
2024-06-14 18:09

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Platform:
Windows

Difficulty:
2.0

Quality:
4.0

Arch:
x86

Downloads:
27

Size:
1.18 MB

Writeups:
0

Comments:
6

Description

crack me with hard-coded encrypted password

Comments (6)
Writeups (0)

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dredge on 2024-07-27 11:57: PZZZWZZZJZZZIZ?

tempy on 2024-09-04 18:22: I don't understand what I am doing wrong. I get all the way to the memcmp call and see the (supposed?) password, but if I try to enter that password I don't even get to the memcmp, instead I already fail in the instruction cmp esi, 3A2h?

CZ-DannyK on 2024-10-19 14:24: So far i have end up in same situation. There are contradictory conditions that cannot be met. I am starting to believe there is something fishy going on, but so far not luck in figuring out what.

dzwassim95 on 2024-11-04 18:31: [Click to reveal]

dzwassim95 on 2024-11-04 18:51: so i think i figued out the first check , which appears to be a type of hash check or checksum , the hash of the correct password should be 3A2h , so i started to find the how the hash is created , then i reached the 2nd check (after 3A2h) and i got bored and i just patched it , this is how the hash or checksum is created : take the first charecter of your key convert it to ascii then multiply the hex value of it with THE HEX value of ZZZP (from PZZZWZZZJZZZIZZZLZZZCZZZ) which is 5A 5A 5A 50 then add FF to it then take the last byte of the result (eg. 5A5A5A50 + 34 = 125A5A5840-- 40) then subtract FF from it. the result is added to the other results when looping through each char of your key with the same previous steps, (the result buffer is initialized to 0)

dzwassim95 on 2024-11-04 18:55: i forgot to mention the key length should be 12 and you should choose the next 4 chars from "PZZZWZZZJZZZIZZZLZZZCZZZ" to multiply with each loop, for example the second loop should choose ZZZW , the third ZZZJ .... then start again ZZZP ...

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danyad29011's crackme lel