Upload:
10:12 AM 10/18/2022
Description
My First CrackMe,This's Very Easy!
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MountainMan on 3:44 AM 10/21/2022: Danof4edx_flag
vcruntime.dll error for me.
jinzi0113@163.com on 9:39 AM 10/21/2022: MountainMan You need to install the vc runtime
HarpoonHarry on 3:27 PM 10/28/2022: flag{Danof4edx_flag}
sultan on 9:25 AM 11/10/2022: pass bdfWaa
xyz on 12:27 PM 11/12/2022: was the objective to just it to say you got it
or to get the actual login details? xd
aovzerk on 12:00 PM 11/13/2022: Login: Danof4edx_flag
Pass: D``R`!bh
Tvorojok on 7:13 PM 11/18/2022: Gen pass - https://prnt.sc/UAwoxS-PzHP6
Valid - https://prnt.sc/TEjs3XmlphRU
testesdrives on 3:45 PM 11/20/2022: solution.c
#include
#include
int main(int argc, char const *argv[])
{
char someRandomString[21] = "flag{Danof4edx_flag}";
char username[255];
printf("Insert Username\n");
scanf("%s", username);
int usernameSize = strlen(username);
int someRandomStringSize = strlen(someRandomString);
int i = 0;
while (1)
{
if (usernameSize
Orkada on 11:44 PM 11/22/2022: 0xc000007b error
wimm on 7:15 PM 12/07/2022: ``` 00F8FD64 "D``R`!bh" ```
SidneyJob on 8:00 AM 12/10/2022: flag{Danof4edx_flag} - this is not flag!
If you want solve this task you need to get string "Congratulations, you did it." with out patching programm
featherfx on 5:58 PM 03/21/2023: put a breakpoint on the string comparison (call ), type in a random username like bob and a password,press enter and the program should break, ECX should hold the password u typed and EAX should hold the password it's expecting for the username bob, restart program enter bob again and paste password. Congrats u cracked it
lilly on 7:12 PM 05/04/2023: I have the feeling many have a really difficult solution. But it basicly only need 1 letter. (thats not a strong password XD)
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