Author:
yxupy

Language:
.NET

Upload:
10:22 PM 05/22/2022

Platform
Windows

Difficulty:
1.0

Quality:
3.7

Arch:
x86-64

Description

My First Crack me. Really Easy.

• Comments
• Solutions

syspher on 12:56 PM 06/01/2022: Login: 8103535 if (this.bunifuTextBox1.Text == "8103535") { this.Lol(); int num = (int) MessageBox.Show("Lel.."); } xD

OpMoya on 11:42 AM 06/25/2022: You seriously? if (this.bunifuTextBox1.Text == "8103535") { this.Lol(); MessageBox.Show("Lel.."); return; } How I done it? I'm found a this.Lol();...

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