Sw1rl's CrackmeApp

Author:
Sw1rl

Language:
C/C++

Upload:
2022-04-23 09:56

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Platform:
Windows

Difficulty:
2.2

Quality:
3.7

Arch:
x86-64

Downloads:
7

Writeups:
1

Comments:
10

Description

Hi everyone! This is my first crackme program experience. You should find password for this, but it's simply encrypted. Archive password is "crackmes.one"

Comments (10)
Writeups (1)

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rrenamed on 2022-05-09 19:57: [Click to reveal]

SMUJ on 2022-05-30 20:41: How can i crack the software when I try to drag it into the dissembler it says i need a password for the zip?

Blepperton on 2022-06-01 11:20: unsafe code. program crashes if input is too long.

Nycz on 2022-06-03 15:35: hint: memory is not written to in correct order

db123 on 2022-06-20 03:09: [Click to reveal]

1337ReverseEngineer on 2022-07-19 23:38: Very nice crackme. Enjoyed it alot.

Marshad on 2022-07-22 01:33: [Click to reveal]

Riria on 2022-08-02 07:13: Learn a lot from it!

f1ref1st on 2022-11-19 17:33: to get the password with the harden password: lst=[0x33, 0x73,0x70,0x31,0x72,0x48,0x2f,0x64,0x64,0x31,0x6e,0x50,0x5f,0x33,0x33,0x75,0x30,0x72,0x64] # harden password lst2=[] for i in lst: lst2.append(int(i+0x1)) for x in lst2: if i%2 == 0: print(chr(i+1), end="") else: print(chr(i-1), end="") #now it will print the password, the algorithm dependence on if the ascii value of the character is even, then add one to it, and if it's odd, then minus one.

CyGhost on 2023-01-21 16:23: https://imgur.com/a/z5FO7Kg i think you need to patch this to find password because it will firstly run code that just display's that password is incorrect and than later it will do a while loop for a correct password

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Solution by 1337ReverseEngineer on 2022-07-20 00:58:
Copyright by islaitala@gmail.com

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