| @X3eRo0 ,hi, i would like ask a question. i have solved the maze problem and get username and password. but the password is not ascii code. of course, this is not correct password. so does it mean there are two or at least two answer to solve maze problem? although the password i get is not ascill code, it can pass check of license.
user =58 de 6c ae 6f 19
password =27 C9 DE 86 19 FE 5D 88 91 6C CD 68 F1 21 AE 96 63 10 B9 DA 0B E5 95 17 D6 A2 96 DA 95 5C F9 6D 09 BD 86 AD 4C 26 DA BA E5 12 CA 44 1C DF 04 D9 06 F5 21 6C 45 66
can i claim i solve this crackme? plz, i gonna die :( |
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| post a comment to record I have solved this crackme.
btw, the final letter of key involves too much calculation process. I think it is too much. |
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| can someone make a solution? it is difficult for me to solve even though i reverse it and rebuild the program. |
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| very nice crackme. i feel like i reverse a really software. |
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| it is not difficult, but too long.
and using time() and mod srand() cause me inconvenient that
i need to input username and password instantly after i run my write-up program. |
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