| Medium Crackme 2TDCX |
PS C:\Users\MMO23\████████████████████████\64680b8133c5d4393891322d> .\2TDCX_CP03.exe
_________ .__ __ __________ .__ __ _ _ _______ ________
\_ ___ \| |__ ____ ____ | | _\______ \____ |__| _____/ |_ __| || |_\ _ \ \_____ \
/ \ \/| | \_/ __ \_/ ___\| |/ /| ___/ _ \| |/ \ __\ \ __ / /_\ \ _(__ <
\ \___| Y \ ___/\ \___| < | | ( <_> ) | | \ | | || |\ \_/ \/ \
\______ /___| /\___ >\___ >__|_ \|____| \____/|__|___| /__| /_ ~~ _\\_____ /______ /
\/ \/ \/ \/ \/ \/ |_||_| \/ \/
Would you like a hint? ;)
5c37553449366c6e5c343d715c7e497e51696c515c7e4657565c746260433174494c46626534497e57434a335141424e56633939
Mission Accomplished! Get your flag!
[+] FIAP{cH3Ck_p0int_zER0_ThR33_nO_ch34t_30302D32422D36372D38302D38452D4545}
PS C:\Users\MMO23\████████████████████████\64680b8133c5d4393891322d>
|
2026-08-29 13:04 |
| Getting started keygen |
[Click to reveal]this Py Script is a Solution for this Crackme
"
s=input("Enter string: ")
print("Correct number:",sum(x^ord(c) for x,c in zip([4,0x4f,0x81,0xab,0xfe,0x7b,0xe0,0xcc,0x46,0x35],s)))
"
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2026-08-26 09:22 |
| Medium Crackme 2TDCX |
this is Solution for this crackme
https://medium.com/@mmo23/medium-crackme-2tdcx-solution-b62a6571bd3b
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2023-05-27 23:58 |
| Medium Crackme 2TDCX |
[Click to reveal]i got the flag
Mission Accomplished! Get your flag!
[+] 43382D44332D46462D37362D39372D4335
|
2023-05-27 20:38 |
| hackme_level_9000 |
[Click to reveal]flag{Sh13sh_R3v3rs3_Engineering_G0dz69}
|
2023-01-24 19:39 |