| FindLicenseKey |
[user@hostname 6a2c61c06840520e01b21e2d]$ ./findlicensekey "hatenal"
Enter license key to continue:
dr2d1s1XlFNGqY9OXXP0AXX3
Key validated
[user@hostname 6a2c61c06840520e01b21e2d]$
code used:
#include <stdio.h>
void generate_license_key(const char *username, char *outKey)
{
static const char charset[] =
"QAZPLWSXOKMEYDCIJNRFVUHBTG"
"qpalzmwoeirutyskdjfhgxncbv"
"1750284369"; // 62 characters
for (int i = 0; i < 24; i++) {
outKey[i] = charset[(username[i] + i) % 62];
}
outKey[24] = '\0';
}
int main(int argc, char** argv) {
char pass[264];
generate_license_key(argv[1], pass);
printf(pass);
return 0;
} |
2026-06-16 09:49 |
| ASCII_CRACK |
CTF{S3cR3T_AsSc1_Fl4g}{@_@}
found using this python script:
def decode(a:str, b:int):
return chr(ord(a)-b)
s = "IYJ~U4cQ1Q[<mL[(U;`'Ynk/M-i"
new_s = ""
for i in range(len(s)):
new_s += decode(s[i], 6-i)
print(new_s) |
2026-04-05 09:18 |
| U Can't Pass |
replace assembly instruction:
0010117c 74 10 JZ LAB_0010118e
with a NOP
[user@hostname ~]$ ./main.out
Hello in my first programm for crackme.one
Success! |
2026-04-05 08:23 |