Number of crackmes:
Number of writeups:
Comments:
| Name | Author | Language | Arch | Difficulty | Quality | Platform | Date | Downloads | Writeups | Comments |
|---|
| Crackme | Date | Infos |
|---|---|---|
| CrackmesForBeginners (CFB) #1 | 2026-05-28 15:56 | |
| Existential Vending Machine | 2026-05-25 16:07 |
| Crackme | Comment | Date |
|---|---|---|
| TooManyChecks | This was a fun crackme to solve! First, the registry check for VM sandboxing and the debugger check using CreateToolhelp32Snapshot API and then the hash generator for checking the .text section if it was changed, everything was fun to solve!! Anyway, here's the flag: [-] Welcome, reverser. This binary does not want to be understood. Enter the flag. This is the easy part: Flag(ByP@$$_a_B0$$) [-] Congrat you won | 2026-05-29 07:38 |
| PlsCrackMe | It just checks for 3 special characters, 3 digits, 4 lower case letters and 3 upper case letters to be present in any order! Please enter the password : &&&456bbbbAAA Good job, You Really Cracked it! | 2026-05-28 18:00 |
| CrackmesForBeginners (CFB) #1 | The actual serial gen algorithm used by this crackme is: y=((i+0x5A)^c)+0x13 NOTE: Check out my writeup for the keygen I wrote! =================================================== Crackme #1 [+] by pwn.by [+] --> pwned.space <-- =================================================== [+] Enter Username (min 4 chars): user [+] Enter Serial Key: 423B4C42 [*] Verifying key... =================================================== [+] ACCESS GRANTED! Congratulations! You have successfully solved CFB1! =================================================== | 2026-05-28 15:54 |
| Existential Vending Machine | Check out my write-up for the full breakdown | 2026-05-25 16:05 |
| Bobs gambling | It is pretty simple. All you have to do is check the line "DAT_1400050fc = (char)choice_input;" because, the program converts our choice input into character and stores it into data section. So, to bypass the check "if (DAT_1400050fc != -1)", we can just simply type in "255" as our choice because unsigned char [(char)0xFF == 255]. And therefore, we will be able to access the hidden admin panel and clear his debt ADMIN TERMINAL 1: Set users debt to zero 2: Exit Selection: 1 [+] Debt cleared. dzctf(bob_is_free_1337) | 2026-05-22 07:51 |
| Adversarial Mind | [*] Password required. Do not attempt to redefine the task: UEFTU1dPUkR7ZmFsc2VfcGFzc3dvcmR9 [*] Correct password. The model resisted the temptation to overthink. | 2026-05-22 07:20 |
| Validator (easy) | no debugger found enter a password VmFsaWRQYXNzd29yZA== goood boy | 2026-05-20 06:52 |
| Very easy | I guess the author mistakenly compared 0 instead of 1 after the strcmp() | 2026-05-15 10:18 |
| Ez Crackme | Это было легко, пидор. string text = "ar@gerg554y345@htw54"; | 2026-05-15 10:10 |
| ACrack | Very simple and easy Mini crackme by @microsoftstorage writed on C! Nickname: CrackMeOne True! Password: t.me/Umno223 True! | 2026-05-15 10:03 |
| GetToKnow-v0.1 | Extremely simple! Yes Enter Password: 1mN0TTh3PwTru5tM3 YOU DID IT! LETS GOOO | 2026-05-15 10:00 |
| Fixed Easy Crackme | Very easy indeed!! Welcome!!! Please Enter The Password: EasyPassword Congrats!!! You Cracked The Code Enter To Exit | 2026-05-15 09:56 |
| very easy crack me $$$ by whekkees | Welcome to my so eazy crack me good luck by whekkees Please enter ur login: whekkes Please enter ur password: qwerty Nice job bro | 2026-05-15 09:50 |
| My First CrackMe | The class Program has the plain text password Pass: password | 2026-05-15 09:38 |
| EasiestEver | I am a beginner but since I knew a bit about instructions, this was quite easy for me! Amazing experience! | 2026-02-09 08:57 |