| Key |
The code is fine. Nothing was that hard. I could have write keygen but not worth for daily xor challenges.
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2026-09-29 02:47 |
| zW0rM |
How to solve this type of code ? I used retsync to synchronize static + dynamic. after more than 13 or 14 functions. found the one function that stores 999999. But couldn't find the one actually does sub-1 if 0 touches @. This is genuienly too hard. I need some suggestions how to approach this kind of code !
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2026-09-28 16:37 |
| Confusion |
[Click to reveal]Obfuscation so goated that i had to pull out ret-sync x64 with ida , found the password check function, returns one by one of the desired output. runs 29 times with get_tickcount followed by isdebugger present, returns one by one rather than all at once. Y, o , u , v , i like this and if bypassed debug check then moves to correct or incorrect password.
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2026-09-25 07:31 |
| Confusion |
Can some one really make a writeup to attack this kind of code ?
Any plugins, tricks, ? i seem to lost here
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2026-09-25 03:37 |
| VeryHard 99% you can't do it |
who the hell rated this 2.0 ? Well gooners, you have to pass it from scratch ! The thing is hardcoded doesn't mean that you can use anti anti-debug to take advantage of ! You must manually map all those things not a single patch.
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2026-09-21 09:28 |
| hshell_secret_of_the_matrix by c0nfig |
Malware alert !!
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2026-09-18 09:10 |
| Level 4 |
I am a beginner in re. Holy cow it took me 7 feaking day to solve. For this problem to be solved, i had to learn microscopic details of c/c++. The mathematical loops must be doing nothing. r8d=sum of decimals. r12=sum x 123, the serialkey=sumofdecimals x 123, it must satisfy the equation.
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2026-09-14 03:53 |
| Level 3 |
I am really progressing with these crackmes. It takes the username , expects the serial key to be a number. doesn't check the total digit entered but it utilizes the username to generate key. Converts all the text into decimal equivalent, sums them all . does multiplication with 1337 and xors the result with 5a5a.
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2026-09-10 07:22 |
| Level 2 |
[Click to reveal]I am beginner here. Yet, I was able to identify that the program expects 7 inputs from the user, xors the input taken with 5ah and expects each one to match with the stored value. Even if one gets wrong the program exits. It has value stored such as ( ) " ; and we have to find the ascii correspondence to convert back to text. The final answer comes reverse.
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2026-09-06 16:16 |
| CRACKME - C |
The quality of the code is really bad !
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2026-08-31 07:26 |
| CRACKME - C |
Gooners really say the CR4CKM3_1234 and declared it as password. The right character must match the ascii value of each in the left of CR4CKME_1234.
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2026-08-31 07:16 |