| Level 6 |
Huh, I could very well be overlooking something. But it seems like we have to patch this. If that's the case, find the lowest 8-bits of the sum of all characters input. In this case, that input needs to 'crack'. I did think that possibly adding extra characters to this to get the required lowest bits would be fine. But there is a length check on the input. So I just brute forced the xor key, used that to find the new key for the lowest 8-bits of the sum of 'crack'. Then patched the new key in. Since I was patching anyway, I changed the stored encoded text so that the output read, "Succeed!" instead of "Sicceed!" |
2026-07-15 04:41 |
| Level 5 |
This one was very similar to the last and was very similar in difficulty. The math involving how key1 should validate itself and validate key2 was interesting especially while needing a specific value for key2 to properly decrypt the flag. "Victory!". Interestingly, I looked at all 2-6 digit numbers, and there are only about 230 and will properly validate for this! I don't really want to bother looking for larger numbers but I know there are. |
2026-07-14 16:08 |
| Level 4 |
This was definitely a little more in depth than the last. While the base logic was very similar to the last level, the addition of using the serial key to decrypt a block of encoded data was interesting. Funnily enough, if you are just looking for the string "Solved" to be printed, there are actually about 86385 different usernames that all generate the same serial key value and will print "Solved!" |
2026-07-13 00:45 |
| easyjerk |
Fun little crackme
serial = "LiZTeETf" |
2025-04-13 06:00 |
| LSDtrip crackme! |
Another PW: [YZY |
2024-11-28 19:07 |