Kakao's NiTiNOL CrackMe

Author:
Kakao

Language:
C/C++

Upload:
2026-06-06 19:14

Download

Platform:
Windows

Difficulty:
2.0

Quality:
4.0

Arch:
x86-64

Downloads:
95

Size:
2.07 MB

Writeups:
0

Comments:
1

Description

Minimal protection :) Outputs "ok" if the correct key is provided. Usage: CrackMe.exe <key>

Comments (1)
Writeups (0)

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koray105 on 2026-06-08 17:47: VM is just an 8-round loop of obfuscated operations. Basically: (A | B) - (A & B) is just XOR. This hides the X ^= X << 13 and X ^= X >> 7 shifts. (A ^ B) + ((A & B) << 1) is just addition. This hides X += 0x9e3779b97f4a7c15. Since everything is invertible, you can solve it backwards from the target 0xf4d1a2c3b5e60718. Valid Key: dT\x16\xb9\xdax\xaa? (0x645416b9da78aa3f) Solver: python def inv_sr(val, shift): res = 0 for i in range(63, -1, -1): bit = ((val >> i) & 1) if i + shift < 64: bit ^= ((res >> (i + shift)) & 1) res |= (bit << i) return res def inv_sl(val, shift): res = 0 for i in range(64): bit = ((val >> i) & 1) if i >= shift: bit ^= ((res >> (i - shift)) & 1) res |= (bit << i) return res X = 0xf4d1a2c3b5e60718 C = 0x9e3779b97f4a7c15 for _ in range(8): X = (X - C) & 0xffffffffffffffff X = inv_sr(X, 7) X = inv_sl(X, 13) print(X.to_bytes(8, 'big'))

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Kakao's NiTiNOL CrackMe