Ulevel's rsame

Author:
Ulevel

Language:
C/C++

Upload:
2026-02-22 12:20

Download

Platform:
Windows

Difficulty:
2.3

Quality:
4.5

Arch:
x86-64

Downloads:
352

Size:
6.09 KB

Writeups:
0

Comments:
11

Description

this is simple rsa-64 crackme patching is not solution Find the correct serial

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Comments (11)
Writeups (0)

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Baranqqqs on 2026-02-23 18:15: 4048192110296323912 is this a correct one ?

Ulevel on 2026-02-23 19:53: Thanks for solving it 🙂 Hope you enjoyed it. Any feedback is welcome.

0xSherfa on 2026-02-23 19:56: [Click to reveal]

Ulevel on 2026-02-23 20:06: Thanks for solving it. I appreciate any feedback on the challenge or design.

Thulina on 2026-02-24 06:45: password

Thulina on 2026-02-24 06:45: "5e884898da28047151d0e56f8dc6292773603d0d6aabbdd62a11ef721d1542d8"

Ulevel on 2026-02-24 11:51: This crackme does not use hashing. It is pure RSA validation.

GautamGreat on 2026-02-25 07:30: def generate_key(): n = 0x954338B7D20E11FD m = 0x16069C61DE505BD6 e = 0x10001 p, q = 2927576537, 3673858757 # Grabbed from factordb.com phi = (p - 1) * (q - 1) d = pow(e, -1, phi) return pow(m, d, n) print(generate_key())

Ulevel on 2026-02-25 13:40: Nice write-up. Yes, the intended path was factoring the 64-bit modulus.

sjdxxx on 2026-02-25 22:59: [Click to reveal]

Ulevel on 2026-02-26 10:14: Yes, confirmed. The serial 4048192110296323912 is correct.

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Ulevel's rsame_v2