VladMetz's Crackme #1

Author:
VladMetz

Language:
C/C++

Upload:
2022-02-19 22:05

Download

Platform:
Windows

Difficulty:
4.0

Quality:
3.5

Arch:
x86

Downloads:
7

Writeups:
1

Comments:
1

Description

I think the difficulty here is not in the anti-debugging methods Good luck :D

Comments (1)
Writeups (1)

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nogame on 2022-02-23 09:46: if((key[14] == key[13]) && (key[10] - key[9] = 0)) { if(key[12] - key[11] = 0) { if(4 * (key[10] - key[9]) * (key[12] - key[11]) * (key[8] - key[7]) == -2912) { // Nice, good work :) } } }

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Solution by ThePhilosopher on 2022-07-03 12:58:
A comprehensive write up.

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crackmes.one

crackmes.one

VladMetz's Crackme #1