Author:
midnight-rev

Language:
C/C++

Upload:
1:21 AM 08/03/2021

Platform
Windows

Difficulty:
2.6

Quality:
3.4

Arch:
x86

Description

The objective is to create a KeyGen for the challenge.

• Comments
• Solutions

monkeyDeniro on 2:03 AM 08/15/2021: int main() { int local_20 = 0; int local_24 = 0; // 012345678 // 1234-5678 char serial[] = "abcd-2312"; for (int i = 0; i (local_20 & 0x1)) + local_24 + serial[8]; } else { local_2c = ((int)serial[3]

monkeyDeniro on 2:04 AM 08/15/2021: SERIAL = abcd-2312 activation key = 38550

4hem on 2:03 PM 10/17/2021: #include int main(){ unsigned int v4; // [esp+0h] [ebp-30h] int v5; // [esp+4h] [ebp-2Ch] BYREF unsigned int v6; // [esp+8h] [ebp-28h] int i; // [esp+Ch] [ebp-24h] unsigned int v8; // [esp+10h] [ebp-20h] int v9; // [esp+14h] [ebp-1Ch] char v10; // [esp+18h] [ebp-18h] char v11; // [esp+19h] [ebp-17h] char v12; // [esp+1Ah] [ebp-16h] char v13; // [esp+1Bh] [ebp-15h] char v14; // [esp+1Ch] [ebp-14h] char v15; // [esp+1Dh] [ebp-13h] char v16; // [esp+1Eh] [ebp-12h] char v17; // [esp+1Fh] [ebp-11h] char Str[]="ABCD-EFGH"; v10 = Str[0]; v11 = Str[1]; v12 = Str[2]; v13 = Str[3]; v14 = Str[5]; v15 = Str[6]; v16 = Str[7]; v17 = Str[8]; v9 = 0; v8 = 0; for ( i = 0; i (v9 & 1)) + v8 + v17; v4 = v6 + v8 + v9; printf("%d\n",v4); }

You must me logged to submit a solution