jeffli6789's bubbly

Author:
jeffli6789

Language:
C/C++

Upload:
2020-07-04 15:28

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Platform:
Unix/linux etc.

Difficulty:
1.5

Quality:
4.0

Arch:
x86-64

Downloads:
17

Size:
6.07 KB

Writeups:
2

Comments:
9

Description

Try to come up with an input that lets the program print "Well done!". Ignore the "cat flag.txt"; the originally challenge was intended for remote validation.

Comments (9)
Writeups (2)

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BinaryNewbie on 2020-07-13 23:27: Solved, thanks for the challenge @jeffli6789

BitFriends on 2020-07-23 15:02: hey jeff, I'm stuck with this crackme. Are at the compare which leads to "Well done!" if true (&dword_201020[20] == v7) two addresses compared?

jeffli6789 on 2020-07-24 05:58: @BitFriends: Nope, I do not think so. It is not comparing addresses

BitFriends on 2020-07-24 15:23: But there is a & in front of it

BitFriends on 2020-07-24 15:25: And if I set rax(&dword_201020[20]) and r13(v7) through gdb to the exact same address I pass...

BitFriends on 2020-07-24 15:25: also v7 contains an address

BitFriends on 2020-07-24 15:26: ignore the "amp;" its from the website

jeffli6789 on 2020-07-27 02:14: Hi BitFriends! If you are talking about the disassembly at line 0x6dc then yes, it is comparing two addresses. But you have to understand why it is doing this, or, what is the criteria it can pass. If you want a faster discussion, you may wish to reach me on discord.

jimsktsmith on 2021-12-29 14:17: Key : print index of buble sort =))

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Solution by BinaryNewbie on 2020-07-14 00:05:
My solution contains a little write-up and a python 3 script.

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Solution by 7cherubin on 2022-07-20 14:18:

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crackmes.one

crackmes.one

jeffli6789's bubbly