Author:
py

Language:
C/C++

Upload:
4:41 AM 01/10/2020

Download

Platform
Windows

Difficulty:
2.0

Quality:
4.0

Arch:
x86

Description

Either you can get the secret(which might be challenging though), and the flag will be provided, or you can just manipulate the program to get the flag directly :). Enjoy!

• Comments
• Solutions

korsader on 6:28 AM 01/31/2020: be fun

tomo0 on 1:41 PM 02/02/2020: FLAG-{Dr0wn1ngDuck} Swapped each jump opcode in the main function (eg jz - jnz) so the flag is output with any input

Trixoden on 11:58 AM 02/04/2020: don't have time to do a full write up but, Secret: FJIJKJMJOJQJSJUJWJYJ Flag: FLAG-{Dr0wn1ngDuck} Addresses 0x00401665 0x004016E8 are used to deobfuscate the secret Secret gets moved into eax at 0x004016EE

travianking on 6:10 AM 03/04/2020: Enter the secret (enter 0 for a hint): 0 Look for these values: 0x9, 0x39 It might be exhaustive to get the actual secret :P So you're welcome to get the flag only.

Harshil55 on 3:36 PM 05/05/2020: Very easy! just change jumps into nop and get the flag directly

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